We are not given a value of P in this problem, so either pick a value
for P and stick with that throughout the problem, or just let P = P.
We have that t = 1, and r = .055. To find the effective rate of interest,
first find out how much money we have after one year:
A = Pert
A = Pe(.055)(1)
A = 1.056541P.
Therefore, after 1 year, whatever the principal was, we now have 1.056541P.
Next, find out how much interest was earned, I, by subtracting the initial amount of money from the final amount:
I = A ? P
= 1.056541P ? P
= .056541P.
Finally, to find the effective rate of interest, use the simple interest formula, I = Prt. So,
I = Pr(1) = .056541P
.056541 = r.
Therefore, the effective rate of interest is 5.65%
Here sum is put on compound interest,
? P.W. = A / (1 + r / 100)n = 2420 / (1 + 10 / 100)2 = 2420 x 100 / 121 = Rs. 2000
? T.D. = P.W. - P
? True discount = 2420 - 2000 = Rs. 420
The Sum of the digits in each number, Except 324 is 10.
The given number series follows the pattern that,
24×0 + 4 = 4
4×1 + 9 = 13
13×2 + 16 = 42
42×3 + 25 = 151
151×4 + 36 = 640
Therefore, the odd number in the given series is 41
From the beginning, the next term comes by adding prime numbers in a sequence of 2, 3, 5, 7, 9, 11, 13... to its previous term. But 165 will not be in the series as it must be replaced by 166 since 153+13 = 166.
The given number series follows a pattern that
196, 169, 144, 121, 100, 81, ?
-27 -25 -23 -21 -19 -17
=> 81 - 17 = 64
Therefore, the series is 196, 169, 144, 121, 100, 81, 64.
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