i=j/m
FV = PV(1+ i)^n
Given, xyz = 1, ax = b, by = c
Now, b = ax
Apply the law of algebra .
Take the power y of both side equation.
? by= axy
Take the power z of both side equation.
? byz = axyz
? ( by )z = axyz
Replace the by with c and xyz with 1 as per given equation,
? cz = a
Here, Let us Assume ,
p = ?56 + ?56 + ?56 + ...........
? p = ?56 + p
Square on both side and solve the above equation.
? p2= 56 + p
? p2 - p= 56
? p(p - 1 ) = 56
? p(p - 1 ) = 8 x 7
? Either p = 8 or p - 1 = 7
? So p = 8;
Now given equation in question is
?56 + ?56 + ?56 + .... ) ÷ 22 = ?
? p ÷ 22 = ?
Put the value of p
? 8 ÷ 22 = ?
? 8 ÷ 4 = ?
? ? = 2;
( 9n x 32 x (3-n/2)-2 - (27)n ) / ( 33m x 23 ) = 1/27
? ( 32n x 32 x 3n - 33n) / ( 33m x 23 ) = 1/27
? ( 32n + n x 32 - 33n) / ( 33m x 23 )= 1/27
? ( 33n x 32 - 33n) / ( 33m x 23 ) = 1/27
? 33n( 32 - 1) / ( 33m x 8 ) = 1/27
? 33n( 9 - 1) / (33m x 8 ) = 1/27
? ( 33n x 8 ) / (33m x 8 ) = 1/27
? 33n / 33m = 1/27
? 33n - 3m = 1/33
? 33( n - m ) = 3-3
3(n - m) = -3
or n - m = -1
or m - n = 1
Given that , 289 = 17x/5
Use the formula if ax = a y then x = y will be true.
? 171/2 = 17x/5
? x /5 = 1/2
? x = 10 .
Apply the law of Fractional Exponents and Laws of Exponents
(am) x (an) = am + n
a-m = 1/am
p0 = 1
and if pX = pY then X will be equal to Y. means X = Y;
(am)n = am x n
(am) x (an) = am + n
am ÷ an = am ? n
Or
am/an = am ? n
Given equation is
2p + 3q = 17 ----------------(i)
2p + 2 - 3q + 1 = 5
? 2p x 22 - 3q x 3 = 5
? 2p x 4 - 3q x 3 = 5
? 4 x 2p - 3 x 3q = 5---------------(ii)
On multiplying Eq. (i) by 3 and adding it, with Eq. (ii), we get
3 x 2p + 3 x 3q = 51
4 x 2p - 3 x 3q = 5
_____________________________
7 x 2p = 56
? 7 x 2p = 7 x 8
? 2p = 8
? 2p = 23
? p = 3
On substituting the value of p in Eq. (i) . we get
23 + 3q = 17
? 8 + 3q = 17
? 3q = 17 - 8
? 3q = 9
? 3q = 32
? q = 2
Given that, (42 x 229) ÷ (9261)1/3 = ?
As we know that (9621)1/3 = (21 x 21 x 21)1/3 = 213x1/3
? 42 x 229 ÷ (213 x )1/3 = ?
? 42 x 229 ÷ 21 = ?
? 42 x 229 x 1/ 21 = ?
? 2 x 229 = ?
? ? = 2 x 229
? ? = 458
?5 + ?x = 3
Apply the law of Algebra Law.
Square both side of equation.
(?5 + ?x)2 = 32
? 5 + ?x = 9
? ?x = 9 - 5
? ?x = 4
Now cube the both side of equation,
? ( ?x ) 3 = 43
? x = (4)3
? x = 64
Given equation is,
( 5 + 2?3 ) / (7 + 4?3 )
Now Multiply and divide by ( 7 - 4?3 ) in above given equation.
By Rationalization, we will get,
[ ( 5 + 2?3 ) / ( 7 + 4?3 ) ] x [ ( 7 - 4?3 ) / ( 7 - 4?3 ) ]
[ ( 5 + 2?3 ) x ( 7 - 4?3 ) ] / [ ( 7 + 4?3 ) x ( 7 - 4?3 ) ]
Apply the formula and multiplication rule of algebra,
( P + Q ) x (R - S ) = P x R - P x S + Q x R - Q x S .................(1)
( a + b ) x ( a - b) = a2 - b2.......................................................(2)
= ( 5 x 7 - 5 x 4?3 + 7 x 2?3 - 2?3 x 4?3 )/ ( 72 - (4?3)2 )
= 35 - 20?3 + 14?3 - 8 x 3 / ( 49 - 16 x 3 )
= ( 35 - 24 - 6?3 )/(49 - 48 )
= 11 - 6?3
? ( 5 + 2?3 ) /( 7 + 4?3 ) = a + b?3
? a + b?3 = 11 - 6?3
on equating the above equation and we get,
or a = 11 and b = - 6
Let the required number be N.
Then, (16/100) x (40/100) x N = 8
Then, N = (8 x 100 x 100) / (16 x 40)
= 125
2/5% = (2/5) /100 = 1/250
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