Amount =
= 8000 x 21/20 x 21/20
= Rs. 8820
Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A =
(P+C.I) =
(P+420) = P[11/10][11/10]
P-1.21P = -420
0.21P = 420
Hence, P = 420/0.21 = Rs. 2000
At first glance it might seem that this problem cannot be solved because we do not have enough
information. It can be solved as long as you double whatever amount you start with. If we start with
$100, then P = $100 and FV = $200.
FV=P(1+r/n)^nt
I. gives, Rate = 5% p.a.
II. gives, S.I. for 1 year = Rs. 600.
III. gives, sum = 10 x (S.I. for 2 years).
Now I, and II give the sum.
For this sum, C.I. and hence amount can be obtained.
Thus, III is redundant.
Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.
Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.
Thus,Rate = =5%
Thus, C.I. for 2 years and therefore, amount can be obtained.
Thus, I is redundant.
FV=P(1+r/n)^nt
i=j/m
n =m(Term) = 2(15.5) =31
Fair market value Present value of the face value
=FV(1+ i)^-n
i=j/m
Maturity value = PV(1 + i)^n
Term = 5 years - 21 months= 3.25 years
Price paid = FV(1+ i )^-n
Let p = Rs. 100.
Then, S.I is Rs. 50 and time = 5 years.
= 10% p.a.
Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a.
C.I. = Rs.
= Rs. 3972
Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 x 240) / (1200) = 20% p.a
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