Let the time required by x seconds.
Then, More cloth means More time (Direct Proportion)
So, 0.128 : 1 :: 25 : x
=> x = 195.31
So time will be approx 195 seconds
There is a meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 120 men.
50 children = =30men
Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in,
1.14 ----- 1
52.0 ------?
= 45.61 sec
Let the required Price be Rs. X .Then, Lest toys , Less cost (Direct Proportion)
Therefore 6 : 5 :: 264.37 : x
=> 6 * x = 5 * 264.37
=> X= 220.308
Therefore, Approximate price of 5 toys = Rs. 220
(Men 14 : 16) : (Hrs/Day 12 : 7) :: 48 : x
14 * 12 * x = 16 * 7 * 48 or x = 32
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
=> 15 * 12 * x = 10 * 18 * 6
=>x = 6
Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,
23:12::276:x => x=(276*12)/23
=> x=144
So price of 12 toys will be Rs. 144
Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
=Rs. [8000 * (23/20) * (23/20) * (21/20)]
= Rs. 11109. .
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.
Let sum=Rs.x
C.I. when compounded half yearly =
C.I. when compounded annually =
=> x=20000
Let the sum be Rs.P.then
P(1+R/100)^3=6690?(i) and P(1+R/100)^6=10035?(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.
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