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- Question
The calendar of the year 2006 was used before in the year?
Options- A. 1990
- B. 1995
- C. 2002
- D. 2000
- Correct Answer
- 1995
ExplanationGiven year 2006, when divided by 4 leaves a remainder of 2.
NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.
So, 2006 - 11 = 1995
- 1. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options- A. Tuesday
- B. Wednesday
- C. Sunday
- D. Friday Discuss
- 2. Akarsh's birthday is on Saturday 29th July. On what day of the week will be Ojas's Birthday in the same year if Ojas was born on 12th August?
Options- A. Wednesday
- B. Friday
- C. Saturday
- D. Sunday Discuss
- 3. How many days are there in k weeks k days ?
Options- A. 8+k days
- B. 7+1k days
- C. 8k days
- D. 7/k days Discuss
- 4. What was the day of the week on 17th June, 1998?
Options- A. Wednesday
- B. Saturday
- C. Friday
- D. Tuesday Discuss
- 5. Oct 1st 1994 falls on which day?
Options- A. Sunday
- B. Saturday
- C. Friday
- D. Wednesday Discuss
- 6. Which of the following year is a leap year?
Options- A. 2500
- B. 1700
- C. 1900
- D. 2400 Discuss
- 7. What was the day on 31st Dec,2011?
Options- A. Monday
- B. Saturday
- C. Sunday
- D. Friday Discuss
- 8. Divyansh's birthday is on Sunday 16th July. On what day of the week will be Shaan's Birthday in the same year if Shaan was born on 1st August?
Options- A. Tuesday
- B. Monday
- C. Wednesday
- D. Sunday Discuss
- 9. Gurkiran's birthday is on Sunday 21st May. On what day of the week will be Shreyas's Birthday in the same year if Shreyas was born on 14th November?
Options- A. Tuesday
- B. Wednesday
- C. Friday
- D. Saturday Discuss
- 10. What was the day of the week on 28th May, 2006?
Options- A. Thrusday
- B. Friday
- C. Saturday
- D. Sunday Discuss
Calendar problems
Search Results
Correct Answer: Sunday
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Correct Answer: Saturday
Correct Answer: 8k days
Explanation:
As we know that a week has 7 days,
k weeks k days = (7k + k) days = 8k days.
Correct Answer: Wednesday
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday
Correct Answer: Saturday
Explanation:
1 Oct, 1994 = (1993 years + Period from 1.1.1993 to 1.10.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
93 years = (70 ordinary years + 23 leap year) = (70 x 1 + 23 x 2)= 4 odd days
Jan Feb March April May June July Aug sept Oct
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 1 ) = 274 days
274 days = (39 weeks + 1 day) =1 odd day.
Total number of odd days = (0 + 1 + 4 + 1) = 6 odd days.
Given day is Saturday.
Correct Answer: 2400
Explanation:
For a century year,it is divided by 400 and leaving a ramainder of 0 results a leap year. So,2400 when divided by 400 leaves a remainder 0.
Correct Answer: Saturday
Correct Answer: Tuesday
Correct Answer: Tuesday
Correct Answer: Sunday
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
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