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- Question
On what dates of April, 2001 did Wednesday fall?
Options- A. 2nd,9th,16th,23rd
- B. 4th,11th,18th,25th
- C. 12th,18th,27th,6th
- D. 1st,8th,15th,22nd
- Correct Answer
- 4th,11th,18th,25th
ExplanationWe shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
- 1. What will be the day of the week 15th August, 2010?
Options- A. Sunday
- B. Saturday
- C. Wednesday
- D. Monday Discuss
- 2. How many days are there in x weeks x days?
Options- A. 7x * x
- B. 8x
- C. 14x
- D. 7 Discuss
- 3. What was the day of the week on 28th May, 2006?
Options- A. Thrusday
- B. Friday
- C. Saturday
- D. Sunday Discuss
- 4. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Options- A. Sunday
- B. Saturday
- C. Friday
- D. Wednesday Discuss
- 5. What was the day of the week on, 16th July, 1776?
Options- A. Tuesday
- B. Wednesday
- C. Monday
- D. Saturday Discuss
- 6. Which two months in a year have the same calendar?
Options- A. October, December
- B. April, November
- C. June, October
- D. April, July Discuss
- 7. On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
Options- A. Saturday
- B. Friday
- C. Monday
- D. Tuesday Discuss
- 8. The maximum gap between two successive leap year is?
Options- A. 4
- B. 8
- C. 2
- D. 1 Discuss
- 9. If Aug 15th,2012 falls on Thursday then June 11th,2013 falls on which day ?
Options- A. Wednesday
- B. Saturday
- C. Monday
- D. Tuesday Discuss
- 10. 26 january 1950 which day of the week?
Options- A. Monday
- B. Wednesday
- C. Thursday
- D. Tuesday Discuss
Calendar problems
Search Results
Correct Answer: Sunday
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.
Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.
Given day is Sunday
Correct Answer: 8x
Explanation:
x weeks x days = (7x + x) days = 8x days.
Correct Answer: Sunday
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Correct Answer: Friday
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
therfore, on 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
Correct Answer: Tuesday
Explanation:
16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.
Correct Answer: April, July
Explanation:
If the period between the two months is divisible by 7, then that two months will have the same calender .
(a). Oct + Nov = 31 + 30 = 61 (not divisible by 7)
(b). Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31 = 214 (not divisible by 7)
(c). Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)
(d). Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)
Hence, April and July months will have the same calendar.
Correct Answer: Friday
Explanation:
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday
S0, 8th Dec, 2006 is Friday.
Correct Answer: 8
Explanation:
This can be illustrated with an example.
Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
Correct Answer: Wednesday
Explanation:
First,we count the number of odd days for the left over days in the given period.
Here,given period is 15.8.2012 to 11.6.2013
Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun
16 30 31 30 31 31 28 31 30 31 11(left days)
2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days
So,given day Thursday + 6 = Wednesday is the required result.
Correct Answer: Thursday
Explanation:
We know that,
Odd days --> days more than complete weeks
Number of odd days in 400/800/1200/1600/2000 years are 0.
Hence, the number of odd days in first 1600 years are 0.
Number of odd days in 300 years = 1
Number of odd days in 49 years = (12 x 2 + 37 x 1) = 61 days = 5 odd days
Total number of odd days in 1949 years = 1 + 5 = 6 odd days
Now look at the year 1950
Jan 26 = 26 days = 3 weeks + 5 days = 5 odd days
Total number of odd days = 6 + 5 = 11 => 4 odd days
Odd days :-
0 = sunday ;
1 = monday ;
2 = tuesday ;
3 = wednesday ;
4 = thursday ;
5 = friday ;
6 = saturday
Therefore, Jan 26th 1950 was Thursday.
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