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- Question
What was the day on 15th august 1947 ?
Options- A. Friday
- B. Saturday
- C. Sunday
- D. Thursday
- Correct Answer
- Friday
Explanation
To find the day of the week for any given date, we can use a formula called Zeller's Congruence. Here are the steps:
- Write down the date: 15th August 1947.
- Day (q) = 15
- Month (m) = 8 (August)
- Year = 1947, so we get:
- K = 47 (last two digits of the year)
- J = 19 (first two digits of the year)
- Apply the formula:
The formula for Zeller's Congruence is:
h = (q + floor(13(m + 1) / 5) + K + floor(K / 4) + floor(J / 4) - 2J) mod 7 - Plug the values into the formula:
h = (15 + floor(13(8 + 1) / 5) + 47 + floor(47 / 4) + floor(19 / 4) - 2(19)) mod 7 - Calculate the terms:
- floor(13(9) / 5) = floor(117 / 5) = 23
- floor(47 / 4) = 11
- floor(19 / 4) = 4
- Final calculation:
h = (15 + 23 + 47 + 11 + 4 - 38) mod 7
Simplified:h = 62 mod 7 = 6 - Interpret the result:
h = 6, which corresponds to Friday (where 0 = Saturday, 1 = Sunday, ..., 6 = Friday).
Thus, 15th August 1947 was a Friday.
- Write down the date: 15th August 1947.
- 1. Ashok can row upstream at 8 kmph and downstream at 12kmph.What is the speed of the stream ?
Options- A. 6 km/hr
- B. 3 km/hr
- C. 2 km/hr
- D. 4.5 km/hr Discuss
- 2. The ratio of the speed of a boat downstream and speed of the stream is 9:1. If the speed of the current is 3 km per hr, find the distance travelled by the boat upstream in 5 hours.
Options- A. 100 km
- B. 98 km
- C. 109 km
- D. 105 km Discuss
- 3. Speeds of a boat along the current and against the current are 14 km/hr and 7 km/hr respectively. What is the speed of boat (in km/hr) in still water?
Options- A. 3.5
- B. 7.5
- C. 10.5
- D. 9.5 Discuss
- 4. A boat goes a certain distance at 40 km/hr and comes back the same distance at 24 km/hr. What is the average speed (in km/hr) for the total journey?
Options- A. 32
- B. 28
- C. 34
- D. 30 Discuss
- 5. A steamer moves with a speed of 4.5 km/h in still water to a certain upstream point and comes back to the starting point in a river which flows at 1.5 km/h. The average speed of steamer for the total journey is
Options- A. 12 km/h
- B. 10 km/h
- C. 6 km/h
- D. 4 km/h Discuss
- 6. Today is Monday. After 61 days, it will be :
Options- A. Tuesday
- B. Monday
- C. Sunday
- D. Saturday Discuss
- 7. What was the day of the week on, 16th July, 1776?
Options- A. Tuesday
- B. Wednesday
- C. Monday
- D. Saturday Discuss
- 8. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Options- A. Sunday
- B. Saturday
- C. Friday
- D. Wednesday Discuss
- 9. What was the day of the week on 28th May, 2006?
Options- A. Thrusday
- B. Friday
- C. Saturday
- D. Sunday Discuss
- 10. How many days are there in x weeks x days?
Options- A. 7x * x
- B. 8x
- C. 14x
- D. 7 Discuss
Calendar problems
Search Results
Correct Answer: 2 km/hr
Explanation:
If the speed downstream is a kmph and the speedup stream is b kmph then
Speed of the stream = 1/2 x (a?b) kmph
Speed downstream a = 12kmph
Speed upstream b = 8 kmph
Speed of the stream = 1/2 x (a?b) = 1/2 x (12?8)= 4/2 = 2 kmph
Correct Answer: 105 km
Explanation:
Let the speed of boat in still water is ?x? km/hr & that of stream is ?y? km/hr.
Then, ATQ
(x+y)/y = 9/1 9y = x + y
x = 8y
y = 3 km/hr
So, x = 24 km/hr
Upstream speed = 24-3 = 21 km/hr
Hence, distance travelled upstream in 5 hours = 21*5 = 105 km.
Correct Answer: 10.5
Correct Answer: 30
Correct Answer: 4 km/h
Explanation:
Speed of streamer = 4.5 km/hrSpeed of water = 1.5 km/hr
Downstream speed = 4.5+1.5 = 6 km/hr
Upstream speed = 4.5 -1.5 = 3 km/hr
Average Speed = (6 X 3) / 4.5 = 4km/hr
Correct Answer: Saturday
Explanation:
Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Correct Answer: Tuesday
Explanation:
16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.
Correct Answer: Friday
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
therfore, on 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
Correct Answer: Sunday
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Correct Answer: 8x
Explanation:
x weeks x days = (7x + x) days = 8x days.
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