To find the day of the week for any given date, we can use a formula called Zeller's Congruence. Here are the steps:
h = (q + floor(13(m + 1) / 5) + K + floor(K / 4) + floor(J / 4) - 2J) mod 7
h = (15 + floor(13(8 + 1) / 5) + 47 + floor(47 / 4) + floor(19 / 4) - 2(19)) mod 7
h = (15 + 23 + 47 + 11 + 4 - 38) mod 7
h = 62 mod 7 = 6
h = 6
, which corresponds to Friday (where 0 = Saturday, 1 = Sunday, ..., 6 = Friday).
Thus, 15th August 1947 was a Friday.
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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