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- Question
Speeds of a boat along the current and against the current are 14 km/hr and 7 km/hr respectively. What is the speed of boat (in km/hr) in still water?
Options- A. 3.5
- B. 7.5
- C. 10.5
- D. 9.5
- Correct Answer
- 10.5
- 1. A boat goes a certain distance at 40 km/hr and comes back the same distance at 24 km/hr. What is the average speed (in km/hr) for the total journey?
Options- A. 32
- B. 28
- C. 34
- D. 30 Discuss
- 2. A steamer moves with a speed of 4.5 km/h in still water to a certain upstream point and comes back to the starting point in a river which flows at 1.5 km/h. The average speed of steamer for the total journey is
Options- A. 12 km/h
- B. 10 km/h
- C. 6 km/h
- D. 4 km/h Discuss
- 3. If a boat goes a certain distance at 30 km/hr and comes back the same distance at 60 km/hr. What is the average speed (in km/hr) for the total journey?
Options- A. 45
- B. 50
- C. 40
- D. 35 Discuss
- 4. Choose the most appropriate answer:A boat travels upstream from B to A and downstream from A to B in 3 hours. If the speed of the boat in still water is 9 Km/h and the speed of the current is 3 Km/h, the distance between A and B is
Options- A. 9 km
- B. 10 km
- C. 11 km
- D. 12 km Discuss
- 5. A boat takes 2 hours to travel from point A to B in still water. To find out its speed upstream, which of the following information is/are required? A. Distance between point A and B. B. Time taken to travel downstream from B to A. C. Speed of the stream of water.
Options- A. Only A and B
- B. Only B and C
- C. All are required
- D. Any one pair of A and B, B and C or C and A is sufficient Discuss
- 6. The ratio of the speed of a boat downstream and speed of the stream is 9:1. If the speed of the current is 3 km per hr, find the distance travelled by the boat upstream in 5 hours.
Options- A. 100 km
- B. 98 km
- C. 109 km
- D. 105 km Discuss
- 7. Ashok can row upstream at 8 kmph and downstream at 12kmph.What is the speed of the stream ?
Options- A. 6 km/hr
- B. 3 km/hr
- C. 2 km/hr
- D. 4.5 km/hr Discuss
- 8. What was the day on 15th august 1947 ?
Options- A. Friday
- B. Saturday
- C. Sunday
- D. Thursday Discuss
- 9. Today is Monday. After 61 days, it will be :
Options- A. Tuesday
- B. Monday
- C. Sunday
- D. Saturday Discuss
- 10. What was the day of the week on, 16th July, 1776?
Options- A. Tuesday
- B. Wednesday
- C. Monday
- D. Saturday Discuss
Boats and Streams problems
Search Results
Correct Answer: 30
Correct Answer: 4 km/h
Explanation:
Speed of streamer = 4.5 km/hrSpeed of water = 1.5 km/hr
Downstream speed = 4.5+1.5 = 6 km/hr
Upstream speed = 4.5 -1.5 = 3 km/hr
Average Speed = (6 X 3) / 4.5 = 4km/hr
Correct Answer: 40
Correct Answer: 12 km
Explanation:
Speed of boat in still water = 9 km/hr
Speed of current = 3km/hr
Downstream speed = 9+3 = 12 km/hr
Upstream speed = 9-3 =6 km/hr
Let the distance between A to B be x km.
x/6 + x/12 = 3x + 2x = 36
3x = 36
x = 12 km
Correct Answer: Any one pair of A and B, B and C or C and A is sufficient
Explanation:
Let distance between A & B = d km
Let speed in still water = x kmph
Let speed of current = y kmph
from the given data,
d/x = 2
From A) we get d
From B) we get d/x+y
From C) we get y
So, Any one pair of A and B, B and C or C and A is sufficient to give the answer i.e, the speed of upstream.
Correct Answer: 105 km
Explanation:
Let the speed of boat in still water is ?x? km/hr & that of stream is ?y? km/hr.
Then, ATQ
(x+y)/y = 9/1 9y = x + y
x = 8y
y = 3 km/hr
So, x = 24 km/hr
Upstream speed = 24-3 = 21 km/hr
Hence, distance travelled upstream in 5 hours = 21*5 = 105 km.
Correct Answer: 2 km/hr
Explanation:
If the speed downstream is a kmph and the speedup stream is b kmph then
Speed of the stream = 1/2 x (a?b) kmph
Speed downstream a = 12kmph
Speed upstream b = 8 kmph
Speed of the stream = 1/2 x (a?b) = 1/2 x (12?8)= 4/2 = 2 kmph
Correct Answer: Friday
Correct Answer: Saturday
Explanation:
Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Correct Answer: Tuesday
Explanation:
16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.
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