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- Question
The banker's discount of a certain sum of money is Rs. 72 and the true discount on the same sum for the same time is Rs. 60. The sum due is:
Options- A. 290
- B. 480
- C. 360
- D. 420
- Correct Answer
- 360
ExplanationSum =(B.D. x T.D.)/(B.D. - T.D.)
= Rs. (72 x 60) / (72 - 60)
= Rs. (72 x 60) /12
= Rs. 360.
- 1. What is the difference between the banker's discount and the true discount on Rs.8100 for 3 months at 5%
Options- A. Rs. 2
- B. Rs. 1.25
- C. Rs. 2.25
- D. Rs. 0.5 Discuss
- 2. The banker's discount on a bill due 6 months hence at 6% is Rs. 18.54. What is the true discount?
Options- A. Rs. 24
- B. Rs. 12
- C. Rs. 36
- D. Rs. 18 Discuss
- 3. If the true discount on a certain sum due 6 months hence at 15% is Rs 120.What is the bankers discount on the same for same time and the same rate.
Options- A. Rs.109
- B. Rs.119
- C. Rs.129
- D. Rs.139 Discuss
- 4. The present worth of a bill due sometime hence is Rs. 1100 and the true discount on the bill is Rs. 110. Find the banker's discount and the banker's gain.
Options- A. Rs.145
- B. Rs.136
- C. Rs.121
- D. Rs.112 Discuss
- 5. If the discount on Rs. 498 at 5% simple interest is Rs.18, when is the sum due?
Options- A. 8 months
- B. 11 months
- C. 10 months
- D. 9 months Discuss
- 6. The certain worth of a certain sum due sometime hence is Rs. 1600 and the true discount is Rs. 160. The banker's gain is:
Options- A. 15
- B. 16
- C. 14
- D. 13 Discuss
- 7. Two consecutive discounts x% and y% is equivalent to the discount
Options- A. (x-y+xy100)%
- B. (x+y+xy100)%
- C. (x-y-xy100)%
- D. (x+y-xy100)% Discuss
- 8. A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:
Options- A. 1.8h
- B. 3h
- C. 4h
- D. 5h Discuss
- 9. A man can row 9 km/h in still water. It takes him twice as long as to row down. Find the rate of stream of the river?
Options- A. 3 1⁄3 Kmph
- B. 3 1⁄9Kmph
- C. 4 2⁄3 Kmph
- D. 4 1⁄3 Kmph Discuss
- 10. A man went downstream for 28 km in a motor boat and immediately returned. It took the man twice as long to make the return trip. If the speed of the river flow were twice as high, the trip downstream and back would take 672 minutes. Find the speed of the boat in still water and the speed of the river flow.
Options- A. 12 km/hr, 3 km/hr
- B. 9 km/hr, 3 km/hr
- C. 8 km/hr, 2 km/hr
- D. 9 km/hr, 6 km/hr Discuss
Banker's Discount problems
Search Results
Correct Answer: Rs. 1.25
Explanation:
F = Rs. 8100
R = 5%
T = 3 months = 1/4 years
Therefore BD - TD = 101.25-100 = Rs.1.25
Correct Answer: Rs. 18
Explanation:
T= 6 months = 1/2 year
R = 6%
Correct Answer: Rs.129
Explanation:
B.G = S.I On T.D
= Rs. (120 * 15 * 1/2 * 1/100)
= Rs.9
B.D - T.D = Rs.9
B.D = Rs.(120 +9) = Rs.129
Correct Answer: Rs.121
Explanation:
T.D. =Ö(P.W.*B.G)
B.G. =(T.D.)2/ P.W.
= Rs.[(110x110)/ 1100]
= Rs. 11.
B.D.= (T.D. + B.G.) = Rs. (110 + 11) = Rs. 121.
Correct Answer: 9 months
Explanation:
F = Rs. 498
TD = Rs. 18
PW = F - TD = 498 - 18 = Rs. 480
R = 5%
=> T = 3/4 years = 9 months
Correct Answer: 16
Explanation:
B.G. =(T.D.)^2/P.W.
= Rs. (160*160)/1600 = Rs. 16.
Correct Answer: (x+y-xy100)%
Correct Answer: 3h
Explanation:
Upstream speed = B-S
Downstream speed = B+s
B-S = 15/5 = 3 km/h
Again B= 4S
Therefore B-S = 3= 3S
=> S = 1 and B= 4 km/h
Therefore B+S = 5km/h
Therefore, Time during downstream = 15/5 = 3h
Correct Answer: 4 2⁄3 Kmph
Explanation:
Let man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr Given: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (a+b) = 28/3 km/hr ½ (x+3x) = 28/3 2x = 28/3 x = 28/ 2 x 3 = 14/3 km/hr rate upstream b = 14/3 km/hr and rate downstream a = 14/3 x 3 = 14 km/hr speed of the current = ½ (a-b) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr
Correct Answer: 9 km/hr, 3 km/hr
Explanation:
Let the speed of the boat = p kmph
Let the speed of the river flow = q kmph
From the given data,
=> 56p - 56q -28p - 28q = 0
=> 28p = 84q
=> p = 3q.
Now, given that if
Hence, the speed of the boat = p kmph = 9 kmph and the speed of the river flow = q kmph = 3 kmph.
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