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- Question
A line cuts the xaxis at the point (3,0) and the yaxis at the point (0,6). What is the equation of the line?
Options- A. x = 2y + 6
- B. y = 2x - 6
- C. x = 2y - 6
- D. y = 2x + 6
- Correct Answer
- y = 2x + 6
- 1. A factory buys 10 machines. 2 MachineA, 3 MachineB and rest MachineC. Prices of the machines are Rs 95000, Rs 60000 and Rs 50000 respectively. What is the average cost of these machines?
Options- A. 62000
- B. 68333
- C. 74666
- D. 60500 Discuss
- 2. A batsman makes 100 runs in the 25th match of his career. His average runs per match increases by 1.4. Find his average before the 25th match.
Options- A. 65
- B. 55
- C. 75
- D. 45 Discuss
- 3. The average of 44 consecutive odd numbers is 144.What is the largest number?
Options- A. 189
- B. 191
- C. 187
- D. 193 Discuss
- 4. The average marks of 18 students in an examination was 60. It was later found that the marks of one student had been wrongly entered as 63 instead of 36. The correct average is:
Options- A. 59
- B. 59.5
- C. 58
- D. 58.5 Discuss
- 5. What is the average of all numbers between 100 and 200 which are divisible by 13?
Options- A. 147.5
- B. 145.5
- C. 143.5
- D. 149.5 Discuss
- 6. The average weight of P, Q and R is 71 kg. If the average weight of P and Q be 66 kg and that of Q and R be 76.5 kg, then the weight (in kg) of Q is.
Options- A. 60
- B. 72
- C. 81
- D. 75 Discuss
- 7. The bankers gain of a certain sum due 2 years hence at 10% per annum is Rs 24 .The percent worth is
Options- A. 400
- B. 800
- C. 500
- D. 600 Discuss
- 8. The banker's discount on a certain sum due 2 years hence is11/10of the true discount. The rate percent is:
Options- A. 10%
- B. 7%
- C. 8%
- D. 5% Discuss
- 9. The banker's discount on Rs. 1650 due a certain time hence is Rs. 165. Find the true discount and the banker's gain.
Options- A. 15
- B. 20
- C. 18
- D. 13 Discuss
- 10. If the true discount on a certain sum due 6 months hence at 15% is Rs. 120, what is the banker's discount on the same sum for the same time and at the same rate?
Options- A. 50
- B. 129
- C. 100
- D. 160 Discuss
Average problems
Search Results
Correct Answer: 62000
Correct Answer: 65
Correct Answer: 187
Correct Answer: 58.5
Correct Answer: 149.5
Correct Answer: 72
Correct Answer: 600
Explanation:
T.D = (B.G * 100) / (Rate * Time)
(24*100) / (10 * 2)
= 120.
P.W = (100 *T.D) / (Rate * Time)
= (100 * 120) /(10 * 2)
= 600
Correct Answer: 5%
Explanation:
Let T.D. be Re. 1.
Then, B.D. = Rs.11/10= Rs. 1.10.
Sum = Rs. (1.10*1)/(1.10-1) = Rs. (110/10)= Rs. 11.
S.I. on Rs. 11 for 2 years is Rs. 1.10
Rate = [(100 x 1.10)/(11 x 2 )]% = 5%.
Correct Answer: 15
Explanation:
Sum = [(B.D.xT.D.)/ (B.D.-T.D.)]
= [(B.D.xT.D.)/B.G.]
T.D./B.G. = Sum/ B.D.
=1650/165
=10
Thus, if B.G. is Re 1, T.D. = Rs. 10.
If B.D.is Rs. ll, T.D.=Rs. 10.
If B.D. is Rs. 165, T.D. = Rs. [(10/11)xl65]
=Rs.150
And, B.G. = Rs. (165 - 150) = Rs, 15.
Correct Answer: 129
Explanation:
B.G. = S.I. on T.D.
= Rs.(120 x 15 x 1/2 x 1/100)
= Rs. 9.
(B.D.) - (T.D.) = Rs. 9.
B.D. = Rs. (120 + 9) = Rs. 129.
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