Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?

Number of boxes = (Volumes of wooden box in cm³) / (Volume of 1 small box)
= (800 x 700 x 600) / (8 x 7 x 6) = 1000000

Let length = 6k, breadth = 5k and height = 4k in cm
? 2(6k x 5k + 5k x 4k + 6k x 4k) = 33300
? 148k² = 33300
? k² = 33300/148 = 225
? k = 15
? Length = 90 cm, Breadth = 75 cm, Height = 60 cm

Volume of cube formed = 216 cm³
? Edge of the cube = (6 x 6 x 6)^1/3 = 6 cm
Surface area of original metal sheet = 2(27 x 8 + 8 x 1 + 27 x 1) cm² = 502 cm²

Surface area of the cube formed = [6 x (6)²] cm² = 216 cm²

? Required difference in area of two solids = (502 - 216) cm²
= 286 cm²

Let the height of cylinder = h
and height cone = H
Then, ?r² h = 1/3 ?r² H
? h/H = 1/3 = 1 : 3

Let the number of spheres be N
Then, N x 4/3 ? x (3)³ = ? x (2)² x 45
? 36N = 180
? N = 180/36 = 5

Radius of sphere = 9 cm
Volume of sphere = [ 4/3 x ? x (9)³] cm³ = 972? cm³
Radius of wire = 0.2 mm = 2/(10 x 10) cm = 1/50 cm
Let the length of wire be = L cm
Then, 972? = ? x (1/50)² x L
? L = (972 x 50 x 50 ) cm
?972? = ? x (1/50)² x L
? L = (972 x 50 x 50) cm
? Length of wire = (972 x 50 x 50)/100 m = 24, 300 m

Let their height be h and 2h radii be x and y respectively.
Then, ?x²h = ?y²(2h)
? x²/y² = 2/1
? x/y = ?2 / 1 = ?2 : 1

? (1/3)?r² x h = ?r² x 5
? h = 15 cm

Let h and H be the height of water level before and after the dropping of the sphere.
Then, [? x (30)² x H ] - [? x (30)² x h ]
= 4/3 ? x (30)³
? ? x 900 x (H -h) = 4/3 ? x 27000
? (H- h) = 40 cm

Area of 4 walls of the room = [2 (l + b ) x h ]m²
Area of 4 walls of new room = [2 (3l + 3b) x 3h]m²
= 9 x [2(l + b) x h ]m²
? Cost of painting the 4 walls of the new room = Rs. (9 x 350)
= Rs. 3150