Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.
Let k be the quantity of third variety of oil in the final mixture.
Let the ratio of initial quantity of oils be 'y'
From given details,
4x + 5 = 5y ..... (1)
5x + 10 = 7y .....(2)
8x + k = 9y ......(3)
By solving (1) & (2), we get
x = 5 & y = 5
From (3) => k = 5
Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.
If any given number (suppose x) is a rational number other than zero, then x0 = 1.
Required triplicate ratio of 7 : 5 = 73 : 53
= 343 : 125
As, S12 = S18
So, S11 = S19
S10 = S20
S9 = S19
.........
.........
.........
S0 = S30
As, S0 = 0
So, S30 = 0
Using the Alligation method ,
Here , C1 = 160 paise , C2 = 145 paise and Mean cost Price ( M ) = 154 paise
Required ratio = ( M - C2 ) : ( C1 - M )
? (Dearer wheat) : (Cheaper wheat) = 9 : 6
Hence , (Dearer wheat) : (Cheaper wheat) = 3 : 2
Average money per head (boy or girl) = Rs. (675 / 75) = Rs. 9
Number of boys = 4 / (4 + 11) × 75 = 20
Number of girls = 11 / (4 + 11) × 75 = 55.
Here , Ratio of milk and water in mixture of 60 litre = 2 : 1
? Quantity of milk = 2y = 40 litre
Quantity of water = y = 20 litre
If ratio of milk and water is to be 1 : 2, then in 40 litres of milk, water should be 80 litre
? Quantity of water to be added = 60 litre.
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