16x + 85 = 17(x + 3)
x = 34 + 3 = 37
The total marks of all 5 subjects = 82 x 5 = 410
Total marks of 1st two subjects = 86.5 x 2 = 173
Total marks of last two subjects = 84 x 2 = 168
Now, marks in 3rd subject = 410 - (173 + 168) = 410 - 341 = 69.
Let the number of boys = b
Let the number of girls = g
From the given data,
81b + 83g = 81.8(b + g)
81.8b - 81b = 83g - 81.8g
0.8b = 1.2g
b/g = 1.2/0.8 = 12/8 = 3/2
=> g : b = 2 : 3
Hence, ratio between the number of girls to the number of boys = 2 : 3.
Total employees =
Hence number of educated employees = 30-20 = 10
We have : ( a + b + c) / 3 = M or (a + b + c) = 3M.
Now. .
Required mean = .
Given Five boxes of bananas sell for Rs. 30.
=> 1 Box of Bananas for = 30/5 = Rs. 6
Then, for Rs. 9
=> 9/6 = 3/2 = 1.5
Hence, for Rs. 9, 1.5 box of bananas can buy.
Given number of boxes = 14
Number of workers = 4
Now, number of whole boxes per worker = 14/4 = 3.5
Hence, number of whole boxes per each coworker = 3
Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]
= Rs. (120 - 94) = Rs. 26.
let the price of one book be Rs. x
Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x
So, x+(8/5)x =26 <=> x =10
The prices of the two books are Rs. 10 and Rs. 16
Numbers of students in section A = x
? Numbers of students in section B and C = (100 ? x)
? x 70 + (100 ? x) 87.5 = 84 100
=> 70x + 87.5 100 ? 87.5x = 8400
=> 8750 ? 17.5x = 8400
=> 17.5x = 8750 ? 8400 => x = 20.
The third proportional of two numbers p and q is defined to be that number r such that
p : q = q : r.
Here, required third proportional of 10 & 20, and let it be 'a'
=> 10 : 20 = 20 : a
10a = 20 x 20
=> a = 40
Hence, third proportional of 10 & 20 is 40.
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