Let average expenditure was Rs. R
13 x 79 + 6x(R + 4) = 19R
=> R = Rs. 80.84
Total money = 19 x 80.84 = Rs. 1536.07.
Given total number of passengers in the bus = 45
First average weight of 45 passengers = 52 kgs
Average weight of 5 passengers who leave bus = 48
Average weight of 5 passengers who joined the bus = 54
Therefore, the net average weight of the bus is given by
Since the month begins with a Sunday, so there will be five Sundays in the month,
Required average = (510 * 5 + 240 * 25) / 30 = 8550/30 = 285.
Let the ratio be x : y
Total boys = 16.4 X x
Total girls = 15.4 X y
Total number of students in class = 16.4x + 15.4y
The average age of all students is 15.8
The total age of boys is 15.8x
The total age of girls is 15.8y
16.4x + 15.4y = 15.8x + 15.8y
0.6 x = 0.4 y
x/y = 0.4/0.6 = 2/3
Using Trial and error method,
we get the number of girls in the hall = 78
Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]
= 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.
Required average = (9.2 / 2) = 4.6.
We have : ( a + b + c) / 3 = M or (a + b + c) = 3M.
Now. .
Required mean = .
Total employees =
Hence number of educated employees = 30-20 = 10
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