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- Question
The length of the diagonal and the breadth of a rectangle are 25 cm and 7 cm respectively. Find its perimeter (in cm).
Options- A. 124
- B. 41
- C. 82
- D. 62
- Correct Answer
- 62
- 1. A right circular cylinder has height 28 cm and radius of base 14 cm. Two hemispheres of radius 7 cm each are cut from each of the two bases of the cylinder. What is the total surface area (in cm2) of the remaining part?
Options- A. 3842
- B. 4312
- C. 3296
- D. 4436 Discuss
- 2. A cube is placed inside a cone of radius 20 cm and height 10 cm, one of its face being on the base of the cone and vertices of opposite face touching the cone. What is the length (in cm) of side of the cube?
Options- A. 5
- B. 6
- C. 8
- D. 9 Discuss
- 3. In the given figure, four identical semicircles are drawn in a quadrant. XA = 7 cm. What is the area (in sq.cm) of shaded region?
Options- A. 70
- B. 140
- C. 77
- D. 84 Discuss
- 4. ABCDEF is a regular hexagon of side 12 cm. What is the area (in cm2) of the triangle ECD?
Options- A. 18?3
- B. 24?3
- C. 36?3
- D. 42?3 Discuss
- 5. The area of a regular hexagon is equal to the area of the square. What is the ratio of the perimeter of the regular hexagon to the perimeter of square?
Options- A. 63 : 36
- B. 23 : 62
- C. 63 : 2
- D. 63 : 23 Discuss
- 6. If a regular polygon has 6 sides then the measure of its interior angle is greater than the measure of its exterior angle by how many degrees?
Options- A. 90°
- B. 100°
- C. 60°
- D. 108° Discuss
- 7. The curved surface area and the slant height of a right circular cone are 99 sq.cm and 9 cm respectively. Find its diameter (in cm)
Options- A. 3.5
- B. 7
- C. 14
- D. 10.5 Discuss
- 8. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
Options- A. 40
- B. 39
- C. 50
- D. 55 Discuss
- 9. The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?
Options- A. 76
- B. 79
- C. 85
- D. 87 Discuss
- 10. The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?
Options- A. 0
- B. -1
- C. 1
- D. none of these Discuss
Area problems
Search Results
Correct Answer: 4312
Correct Answer: 8
Correct Answer: 84
Correct Answer: 36?3
Correct Answer: 63 : 23
Correct Answer: 60°
Correct Answer: 7
Correct Answer: 39
Explanation:
Let the average after 17th innings = x
Then average after 16th innings = (x - 3)
Therefore 16 × (x - 3) + 87 = 17x
Therefore x = 39
Correct Answer: 76
Explanation:
Average = total runs / no.of innings = 32
So, total = Average x no.of innings = 32 x 10 = 320.
Now increase in avg = 4runs. So, new avg = 32+4 = 36runs
Total runs = new avg x new no. of innings = 36 x 11 = 396
Runs made in the 11th inning = 396 - 320 = 76
Correct Answer: 0
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers = (0 * 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).
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