Discussion
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- Question
ABCDEF is a regular hexagon of side 12 cm. What is the area (in cm2) of the triangle ECD?
Options- A. 18?3
- B. 24?3
- C. 36?3
- D. 42?3
- Correct Answer
- 36?3
- 1. ABC is an isosceles right angled triangle having ?C = 90°. If D is any point on AB, then AD2+ BD2 is equal to
Options- A. CD2
- B. 2CD2
- C. 3CD2
- D. 4CD2 Discuss
- 2. An equilateral triangle of side 6 cm is inscribed in a circle. Then radius of the circle is
Options- A. 2?3 cm
- B. 3?2 cm
- C. 4?3 cm
- D. ?3 cm Discuss
- 3. If the parallel sides of a trapezium are 8 cm and 4 cm, M and N are the mid points of the diagonals of the trapezium, then length of MN is
Options- A. 12 cm
- B. 6 cm
- C. 1 cm
- D. 2 cm Discuss
- 4. D and E are points on side AB and AC of ?ABC. DE is parallel to BC. If AD:DB = 2:3, what is the ratio of area of ?ADE and area of quadrilateral BDEC?
Options- A. 4 : 21
- B. 4 : 25
- C. 4 : 29
- D. 4 : 9 Discuss
- 5. ?ABC is similar to ?PQR. If ratio of perimeter of ?ABC : perimeter of ?PQR is 5:9 and if PQ = 45 cm, then the length of AB (in cm) is?
Options- A. 15
- B. 20
- C. 25
- D. 16 Discuss
- 6. Two circles touch each other at point X. A common tangent touch them at two distinct points Y and Z. If another tangent passing through X cut YZ at A and XA= 16 cm, then what is the value (in cm) of YZ?
Options- A. 18
- B. 24
- C. 16
- D. 32 Discuss
- 7. All sides are congruent in a _____.
Options- A. Rectangle
- B. Parallelogram
- C. Rhombus
- D. Kite Discuss
- 8. The area of a circular cricket ground is 24.64 hectares. Find the cost of making rope boundary at the rate of Rs. 5.40 per metre.
Options- A. Rs. 9,600
- B. Rs. 9,504
- C. Rs. 9,802
- D. Rs. 9,876 Discuss
- 9. A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Options- A. Rs. 456
- B. Rs. 458
- C. Rs. 558
- D. Rs. 568 Discuss
- 10. If the radius of a circle is decreased by 50%, find the percentage decrease in its area.
Options- A. 55%
- B. 65%
- C. 75%
- D. 85% Discuss
Area problems
Search Results
Correct Answer: 2CD2
Correct Answer: 2?3 cm
Correct Answer: 2 cm
Correct Answer: 4 : 21
Correct Answer: 25
Correct Answer: 32
Correct Answer: Rhombus
Correct Answer: Rs. 9,504
Correct Answer: Rs. 558
Explanation:
Area to be plastered= [2(l + b) x h] + (l x b)
= [2(25 + 12) x 6] + (25 x 12)
= (444 + 300)
= 744
Cost of plastering = Rs. 744 x (75/100)= Rs. 558
Correct Answer: 75%
Explanation:
Let original radius = R.
New radius = =
Original area = and new area =
Decrease in area = = 75%
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