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- Question
There is a square field of area ?X? square meters. A cylindrical ditch of radius 7 meters and depth 2 meters is dug, and the earth is taken out and spread over the remaining part of the square field, the height of square field which goes up by 0.77 meters. What is the value of ?X? ?
Options- A. 548 sq. m
- B. 524 sq. m
- C. 518 sq. m
- D. 554 sq. m
- Correct Answer
- 554 sq. m
ExplanationVolume of the cylindrical ditch = ?rxrh = 22/7 ×7×7×2 = 308 sq.m
Area of remaining field = (X ??rxr) sq.m
= (X ? 154)
ATQ ?
(X ? 154) ×0.77 = 308
(X ? 154) = 400
X= 554 sq.m
- 1. If the distance between two points (0,?5) and (x,0) is 13 unit, then x =
Options- A. 10
- B. ± 10
- C. 12
- D. ± 12 Discuss
- 2. Find the value of log 322 8 + log 2433 7 - log 361296?
Options- A. 3
- B. 2
- C. 1
- D. 0 Discuss
- 3. In a quadrilateral ABCD, ?B = 90° and AD 2 = AB 2 + BC 2 + CD 2, then ?ACD is equal to:
Options- A. 90°
- B. 60°
- C. 30°
- D. 20° Discuss
- 4. If 31% of a number is 46.5,the number is?
Options- A. 150
- B. 155
- C. 160
- D. 165 Discuss
- 5. A and B can do a piece of work in 18 days, B and C in 24 days, A and C in 36 days. In what time can they do it all working together?
Options- A. 12 days
- B. 13 days
- C. 16 days
- D. 26 days Discuss
- 6. The taxi charges in a city contain fixed charges and additional charge per kilometer. The fixed charge is for a distance of up to 5 km and additional charge per kilometer thereafter. The charge for a distance of 10 km is ? 350 and for 25 km is ? 800. The charge for a distance of 30 km is
Options- A. ? 800
- B. ? 750
- C. ? 900
- D. ? 950 Discuss
- 7. The present worth of a bill of ?1764 due for 2 years at 5 % compound interest is :
Options- A. ?1650
- B. ?1700
- C. ?1600
- D. ?1714 Discuss
- 8. (0.49)4 x (0.343)4 ÷ (0.2401)4 x = (70 ÷ 100)? + 3 ?
Options- A. 3
- B. 1
- C. 4
- D. 7 Discuss
- 9. In a group of 1000 people, there are 750 people who can speak Hindi and 400 who can speak English. How many can speak Hindi only?
Options- A. 600
- B. 650
- C. 750
- D. 800 Discuss
- 10. There are 200 question in a 3 hour examination. Among 200 question, 50 are Mathematics, 100 are from GK and 50 are from Sciences. Ram spent twice as much time on each Mathematics question for each other question. How many minute did he spend on Mathematics questions?
Options- A. 36
- B. 72
- C. 100
- D. 60 Discuss
More questions
Correct Answer: 12
Explanation:
According to question , we have
?( x - 0 )2 + ( 0 + 5 )2 = 13
? x2 + 25 = 169
? x2 = 169 - 25 = 144
? x = ?144 = 12
Correct Answer: 1
Explanation:
Exp. =log3228 + log24337 - log361296
= log25 28 + log35 37 - log36 362
= (8/5)log22 + (7/5)log33 - 2log3636
= 8/5 + 7/5 - 2 = 1
Correct Answer: 90°
Explanation:
In a quadrilateral ABCD,
Given :- ?B = 90°
AB2 + BC2 + CD2 = AC2 + CD2 = AD2 { ? In triangle ABC , AB2 + BC2 = AC2 }
So, in triangle ACD, angle opposite to AD = 90° ( by Converse of Pythagoras theorem)
? ?ACD = 90°
Correct Answer: 150
Explanation:
Let 31% of A = 46.5
? (31 x A)/100 = 46.5
? A = (46.5 x 100) / 31 = 150
Correct Answer: 16 days
Explanation:
(A + B)'s 1 day's work = 1/18
(B + C)'s 1 day's work = 1/24
(A + C)'s 1 day's work = 1/36
Adding 2 (A + B + C)'s 1 day's work = (1/18 + 1/24 + 1/36) = 1/8
? (A + B + C)'s day's work = 1/16
Hence, all working together can finish it in 16 days.
Correct Answer: ? 950
Explanation:
let the fixed charges = ? p for first 5 km
and the additional charges = ? q per km
according to the question
p + 5q = 350........... (1)
p + 20q = 800...........(2)
on subtracting Eq. 1 from Eq. 2 we get
15q = 450
q = 30
On putting the value of q in Eq. (1) we get
p = 200
? charge for a distance of 30 km = p + 25q
= 200 + 30 x 25 = ? 950
Correct Answer: ?1600
Explanation:
Correct Answer: 1
Explanation:
The given question is,
(70 ÷ 100)? + 3 = (0.49)4 x (0.343)4 ÷ (0.2401)4
As we know that
70 ÷ 100 = 0.7
0.49 = 0.7 2
0.343 = 0.7 3
0.2401 = 0.7 4
Put these value in given question , we will get
? (0.7)? + 3 = (0.72)4 x ( 0.73 )4 ÷ ( 0.74 )4
? (0.7) ? + 3 = 0.7 2 x 4 x 0.7 3 x 4 ÷ 0.7 4 x 4
? (0.7) ? + 3 = 0.7 8 x 0.7 12 ÷ 0.7 16
Apply the law of Fractional Exponents and Laws of Exponents
(am)(an) = am+n
am÷an=am-n
Or
am/an=am - n
we will get,
? (0.7)? + 3 = (0.7) 8 + 12 - 16
? (0.7)? + 3 = (0.7) 20 - 16
? (0.7)? + 3 = (0.7) 4
On comparing the exponents both sides, we get
? + 3 = 4
? ? = 4 - 3 = 1
Correct Answer: 600
Explanation:
Given in the question,
n(H ? E) = 1000, n(H) = 750, n(E) = 400
Use the below formula,
n(H ? E) = n(H) + n(E) ? n(H ? E)
We get 1000 = 750 + 400 ? n(H ? E)
? n(H ? E) = 1150 ? 1000 = 150.
Number of People who can speak Hindi only
= n(H ? E?) = n(H) ? n(H ? E)
= 750 ? 150 = 600.
Correct Answer: 72
Explanation:
Let Ram spends p minute on each Mathematics question.
According to the question.
50 x p + 100 x p/2 + 50 x p/2 = 3 x 60
p(50+ 50 + 25) = 180
? p = 180/125
? Required time = 50 x 180/125
? Required time = 2 x 180/5
? Required time = 2 x 36 = 72 min
Method 2
Let Ram spends a minute on each sciences and Gk questions.
According to the question,
50 x 2a + 150 x a = 3 x 60
100a + 150a = 180
250a = 180
a = 180/250
So total time spend on Mathematics question = 2a x 50 question
So total time spend on Mathematics question = 2 x 50 x 180/250 = 72 minutes
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