Let the breadth of rectangle be x cm => Length of rectangle = (x+3) cm Now, perimeter =2(x+x+3) = 50 => 2x + 3 = 25 => x = 11 Thus, breadth = 11 cm and length = 14 cm Area of circle = Area of rectangle =>pi * r* r = 14 * 11 =>r*r = 14 * 11 * 7/22 =>r = 7 cm Diameter = 2 * 7 = 14 cm
Volume of the cylindrical ditch = ?rxrh = 22/7 ×7×7×2 = 308 sq.m
Area of remaining field = (X ??rxr) sq.m
= (X ? 154)
ATQ ?
(X ? 154) ×0.77 = 308
(X ? 154) = 400
X= 554 sq.m
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