Area of a square with side a = aČ sq unts
Area of a triangle with base a = (1/2) * a * h sq.unts
aČ =1/2 *a *h
=> h = 2a
altitude of the triangle is 2a
let the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m. 26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Perimeter of a square p=4s ,where s=length of its side
=> p=4(14)=56 feets
Area of a square A = s x s
=> A=196
The perimeter is 56 feet, and the area is 196 square feet.
let each have base = b and height = h
then p = b*h, R = b*h and T = (1/2) * b*h
so P = R, P = 2T and T = (1/2)*R are all correct statements
let the side of the square be x meters
length of two sides = 2x meters
diagonal =
= 1.414x m
saving on 2x meters = .59x m
saving % = %
= 30% (approx)
A=LB
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