100 cm is read as 102 cm
a = 100 x 100 sq.cm and b = 102 x 102 sq.cm
then, Increase in area = [ (102 x 102) - (100 x 100) ] sq.cm
percentage error = = 4.04%
square and a rectangle with equal areas will satisfy the
relation p < q
Let the length of the altitude be h.
Then, h =
=
= 4.5
We have: l = 20 ft and lb = 680 sq. ft.So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.
Let original length = x and original breadth = y.
Decrease in area = xy - = (7/25)xy
Decrease % = (7/25)xy * (1/xy) * 100 = 28%
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