Let the length of the rectangle be 3x and breadth be 1x
Given, perimeter = 96 m
2(l + b) = 96 (or) l + b = 48 (or) 3x + 1x = 48 (or) x = 12 m
Now, Length of the rectangle = 12 x 3 = 36 m
Let the breadth of rectangle be x m.
Then, the length of rectangle = (x+ 6) m
Perimeter of rectangle = 2 (x+x+ 6) m
Therefore, 2 (x+x+ 6) = 84 m
4x+ 12 = 84
4x= 84 ?12
4x = 72/4 = 18
Therefore, length of rectangle = 18 + 6 = 24 m = height of triangle
Diagonal of rectangle = ?(324+576) = 30 m = base of triangle
Therefore, are of triangle =1/2× base × height =1/2× 24 × 30 = 360 sq. m
Let original length = x and original breadth = y.
Decrease in area = xy - = (7/25)xy
Decrease % = (7/25)xy * (1/xy) * 100 = 28%
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