In this type of question, we will first calculate the distance covered in given time.
Distance covered will be : Number of revolutions x Circumference
So we will be having distance and time, from which we can calculate the speed.
Radius of wheel = 70 / 2 = 35 cm
Distance covered in 40 revolutions will be = 88 m
Distance covered in 1 sec =
area of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15.
Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5
a = = 90 sq.cm
b = 2a =
h= 18cm
let inner radius be r meters.
Therefore, Radius of outer circle = 70 + 14 = 84m
Because each vertice of the square is the center of a circle
(1/4) part of the total area of each circle inside of the square.
(3/4) part of the total area of each circle outside of the square.
Thus total area outside the square is
= 115.3955 sq cm.
Area = (l + b ? d) d
= (80 + 60 ? 10)10
=> 1300 sq.mts
=> 1300 x 3 = Rs.3900
Let the breadth of rectangle be x m.
Then, the length of rectangle = (x+ 6) m
Perimeter of rectangle = 2 (x+x+ 6) m
Therefore, 2 (x+x+ 6) = 84 m
4x+ 12 = 84
4x= 84 ?12
4x = 72/4 = 18
Therefore, length of rectangle = 18 + 6 = 24 m = height of triangle
Diagonal of rectangle = ?(324+576) = 30 m = base of triangle
Therefore, are of triangle =1/2× base × height =1/2× 24 × 30 = 360 sq. m
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