Discussion
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- Question
The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is :
Options- A. 260m
- B. 280m
- C. 360m
- D. none of these
- Correct Answer
-
- 1. The lengths of diagonals of a rhombus are 24cm and 10cm the perimeter of the rhombus (in cm ) is :
Options- A. 52
- B. 56
- C. 68
- D. 72 Discuss
- 2. The perimeter of an isosceles triangle is 32 cm and each of the equal sides is 5/6 times of the base. What is the area (in cm2 ) of the triangle ?
Options- A. 39
- B. 48
- C. 57
- D. 64 Discuss
- 3. A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ?
Options- A. Rs. 345.15
- B. Rs. 245.1
- C. Rs. 234.18
- D. Rs. 456.65 Discuss
- 4. The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ?
Options- A. 14:9
- B. 13:12
- C. 16:5
- D. 17:13 Discuss
- 5. If the ratio of two squares is 225:256,then the ratio of the perimeters is
Options- A. 25:16
- B. 15:16
- C. 16:15
- D. 17:16 Discuss
- 6. The wheel of a motorcycle 70cm in diameter makes 40 revolutions in every 10sec.What is the speed of motorcycle n km/hr?
Options- A. 13.68kmph
- B. 31.68kmph
- C. 41.68kmph
- D. 45.68kmph Discuss
- 7. The base of a triangle of 15cm and height is 12cm. The height of another triangle of double the area having the base 20cm is
Options- A. 16
- B. 17
- C. 18
- D. 20 Discuss
- 8. The inner circumference of a circular race track, 14m wide is 440m. Find the radius of the outer circle.
Options- A. 84m
- B. 24m
- C. 44m
- D. 54m Discuss
- 9. If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ?
Options- A. 119.21 sq cm
- B. 115.395 sq cm
- C. 104.214 sq cm
- D. 111.241 sq cm Discuss
- 10. A rectangular lawn of dimensions 80 m x 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m ?
Options- A. Rs. 3600
- B. Rs. 3800
- C. Rs. 3900
- D. Rs. 3700 Discuss
Area problems
Search Results
Correct Answer: 52
Correct Answer: 48
Correct Answer: Rs. 345.15
Explanation:
area of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15.
Correct Answer: 16:5
Explanation:
Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5
Correct Answer: 15:16
Explanation:
Correct Answer: 31.68kmph
Explanation:
In this type of question, we will first calculate the distance covered in given time.
Distance covered will be : Number of revolutions x Circumference
So we will be having distance and time, from which we can calculate the speed.
Radius of wheel = 70 / 2 = 35 cm
Distance covered in 40 revolutions will be = 88 m
Distance covered in 1 sec =
Correct Answer: 18
Explanation:
a = = 90 sq.cm
b = 2a =
h= 18cm
Correct Answer: 84m
Explanation:
let inner radius be r meters.
Therefore, Radius of outer circle = 70 + 14 = 84m
Correct Answer: 115.395 sq cm
Explanation:
Because each vertice of the square is the center of a circle
(1/4) part of the total area of each circle inside of the square.
(3/4) part of the total area of each circle outside of the square.
Thus total area outside the square is
= 115.3955 sq cm.
Correct Answer: Rs. 3900
Explanation:
Area = (l + b ? d) d
= (80 + 60 ? 10)10
=> 1300 sq.mts
=> 1300 x 3 = Rs.3900
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