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- Question
The lengths of diagonals of a rhombus are 24cm and 10cm the perimeter of the rhombus (in cm ) is :
Options- A. 52
- B. 56
- C. 68
- D. 72
- Correct Answer
- 52
- 1. The perimeter of an isosceles triangle is 32 cm and each of the equal sides is 5/6 times of the base. What is the area (in cm2 ) of the triangle ?
Options- A. 39
- B. 48
- C. 57
- D. 64 Discuss
- 2. A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ?
Options- A. Rs. 345.15
- B. Rs. 245.1
- C. Rs. 234.18
- D. Rs. 456.65 Discuss
- 3. The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ?
Options- A. 14:9
- B. 13:12
- C. 16:5
- D. 17:13 Discuss
- 4. If the ratio of two squares is 225:256,then the ratio of the perimeters is
Options- A. 25:16
- B. 15:16
- C. 16:15
- D. 17:16 Discuss
- 5. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 40
- B. 120
- C. 50
- D. None of these Discuss
- 6. The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is :
Options- A. 260m
- B. 280m
- C. 360m
- D. none of these Discuss
- 7. The wheel of a motorcycle 70cm in diameter makes 40 revolutions in every 10sec.What is the speed of motorcycle n km/hr?
Options- A. 13.68kmph
- B. 31.68kmph
- C. 41.68kmph
- D. 45.68kmph Discuss
- 8. The base of a triangle of 15cm and height is 12cm. The height of another triangle of double the area having the base 20cm is
Options- A. 16
- B. 17
- C. 18
- D. 20 Discuss
- 9. The inner circumference of a circular race track, 14m wide is 440m. Find the radius of the outer circle.
Options- A. 84m
- B. 24m
- C. 44m
- D. 54m Discuss
- 10. If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ?
Options- A. 119.21 sq cm
- B. 115.395 sq cm
- C. 104.214 sq cm
- D. 111.241 sq cm Discuss
Volume and Surface Area problems
Search Results
Correct Answer: 48
Correct Answer: Rs. 345.15
Explanation:
area of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15.
Correct Answer: 16:5
Explanation:
Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5
Correct Answer: 15:16
Explanation:
Correct Answer: None of these
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m. 26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Correct Answer:
Correct Answer: 31.68kmph
Explanation:
In this type of question, we will first calculate the distance covered in given time.
Distance covered will be : Number of revolutions x Circumference
So we will be having distance and time, from which we can calculate the speed.
Radius of wheel = 70 / 2 = 35 cm
Distance covered in 40 revolutions will be = 88 m
Distance covered in 1 sec =
Correct Answer: 18
Explanation:
a = = 90 sq.cm
b = 2a =
h= 18cm
Correct Answer: 84m
Explanation:
let inner radius be r meters.
Therefore, Radius of outer circle = 70 + 14 = 84m
Correct Answer: 115.395 sq cm
Explanation:
Because each vertice of the square is the center of a circle
(1/4) part of the total area of each circle inside of the square.
(3/4) part of the total area of each circle outside of the square.
Thus total area outside the square is
= 115.3955 sq cm.
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