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- Question
A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ?
Options- A. Rs. 345.15
- B. Rs. 245.1
- C. Rs. 234.18
- D. Rs. 456.65
- Correct Answer
- Rs. 345.15
Explanationarea of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15. - 1. The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ?
Options- A. 14:9
- B. 13:12
- C. 16:5
- D. 17:13 Discuss
- 2. If the ratio of two squares is 225:256,then the ratio of the perimeters is
Options- A. 25:16
- B. 15:16
- C. 16:15
- D. 17:16 Discuss
- 3. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 40
- B. 120
- C. 50
- D. None of these Discuss
- 4. A man walking at the speed of 4 kmph crosses a square field diagonally in 3 meters.The area of the field is
Options- A. 10000
- B. 20000
- C. 30000
- D. 40000 Discuss
- 5. Let A(O,-1), B(0,3) and C(2,1) be three points. Let ?1 be the area of the triangle ABC and ?2 be the area of the triangle formed by the mid points of the sides of the triangle whose vertices are A, B and C such that ?1 =1 , ?2=x Find the value of x .
Options- A. 4
- B. 5
- C. 2
- D. 3 Discuss
- 6. The perimeter of an isosceles triangle is 32 cm and each of the equal sides is 5/6 times of the base. What is the area (in cm2 ) of the triangle ?
Options- A. 39
- B. 48
- C. 57
- D. 64 Discuss
- 7. The lengths of diagonals of a rhombus are 24cm and 10cm the perimeter of the rhombus (in cm ) is :
Options- A. 52
- B. 56
- C. 68
- D. 72 Discuss
- 8. The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is :
Options- A. 260m
- B. 280m
- C. 360m
- D. none of these Discuss
- 9. The wheel of a motorcycle 70cm in diameter makes 40 revolutions in every 10sec.What is the speed of motorcycle n km/hr?
Options- A. 13.68kmph
- B. 31.68kmph
- C. 41.68kmph
- D. 45.68kmph Discuss
- 10. The base of a triangle of 15cm and height is 12cm. The height of another triangle of double the area having the base 20cm is
Options- A. 16
- B. 17
- C. 18
- D. 20 Discuss
Area problems
Search Results
Correct Answer: 16:5
Explanation:
Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5
Correct Answer: 15:16
Explanation:
Correct Answer: None of these
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m. 26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Correct Answer: 20000
Explanation:
speed of the man = 4 x (5/18) m/sec = 10/9 m/sec
time taken = 3 x 60 sec = 180 sec
length of diagonal = speed x time = (10/9) x 180 = 200m
Area of the field = (1/2) x (dioagonal)²
= (1/2) x 200 x 200 sq.m = 20000sq.m
Correct Answer: 3
Correct Answer: 48
Correct Answer: 52
Correct Answer:
Correct Answer: 31.68kmph
Explanation:
In this type of question, we will first calculate the distance covered in given time.
Distance covered will be : Number of revolutions x Circumference
So we will be having distance and time, from which we can calculate the speed.
Radius of wheel = 70 / 2 = 35 cm
Distance covered in 40 revolutions will be = 88 m
Distance covered in 1 sec =
Correct Answer: 18
Explanation:
a = = 90 sq.cm
b = 2a =
h= 18cm
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