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- Question
A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ?
Options- A. 115
- B. 117
- C. 116
- D. 114
- Correct Answer
- 117
ExplanationLength = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117. - 1. The edge of three cubes of metal is 3 m, 4 m and 5 m. They are melted and formed into a single cube. Find the edge of the new cube ?
Options- A. 15 m
- B. 4 m
- C. 6 m
- D. 9 m Discuss
- 2. 2 metres broad pathway is to be constructed around a rectangular plot on the inside. The area of the plots is 96 sq.m. The rate of construction is Rs. 50 per square metre. Find the total cost of the construction?
Options- A. 20
- B. 30
- C. 40
- D. data is inadequate Discuss
- 3. A triangle has a perimeter 13. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?
Options- A. 4
- B. 6
- C. 8
- D. None of the above Discuss
- Option A cannot be correct because 4 would not be the longest side.(sides 4, 5, and 4)
- Option B could be correct because the other two sides would be 3 and 4.
- Option C cannot be correct because this third side would be greater than the sum of the other two sides.
- 4. A 3 by 4 rectangle is inscribed in circle. What is the circumference of the circle?
Options- A. 2.5?
- B. 3?
- C. 5?
- D. 4? Discuss
- 5. The perimeter of a rectangle is 160 cm. The rectangle is 4 times longer than wide. What are the length and width of this rectangle?
Options- A. l=65;b=16
- B. l=16;b=64
- C. l=64;b=16
- D. l=16;b=48 Discuss
- 6. Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ?
Options- A. 720
- B. 600
- C. 660
- D. 6000 Discuss
- 7. Chord AB of a circle when extended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of PT and PB are 6 cm and 4 cm respectively, what is the length of PA?
Options- A. 12 cm
- B. 11 cm
- C. 10 cm
- D. 9 cm Discuss
- 8. A parallelogram PQRS, the length of whose sides are 8 cm and 12 cm, has one diagonal 10 cm long Ile length of the other diagonal is approximately:
Options- A. 17.8 cm
- B. 17.5 cm
- C. 17 cm
- D. 18 cm Discuss
- 9. Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.
Options- A. 5
- B. 4
- C. 3
- D. 2 Discuss
- 10. The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
Options- A. 12
- B. 24
- C. 36
- D. 48 Discuss
Area problems
Search Results
Correct Answer: 6 m
Explanation:
The edge of the new cube is = => a = 6 m.
Correct Answer: data is inadequate
Explanation:
Given lb =96
Area of pathway = [(l-4)(b-4)-lb] = 16-4(l+b)
Which cannot be determined. so, data is inadequate.
Correct Answer: 6
Explanation:
The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers.
Correct Answer: 5?
Explanation:
Draw the diagram. The diagonal of the rectangle is the diameter of the circle. The diagonal is the hypotenuse of a 3,4,5 triangle and is therefore, 5.
Circumference = ?.diameter = 5?
Correct Answer: l=64;b=16
Explanation:
P=2(l+b)
l=4b
Correct Answer: 720
Explanation:
Let the number of bricks be 'N'
10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N
10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.
Correct Answer: 9 cm
Correct Answer: 17.8 cm
Correct Answer: 4
Explanation:
let the inner and outer radii be r and R meters
then,
= 352/7
=> r = (352/7) * (7/22) * (1/2) = 8m
= 528/7
=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m
Correct Answer: 24
Explanation:
side of first square = 40/4 =10cm
side of second square = 32/4 = 8cm
area of third squre = 10² - 8² = 36 sq cm
side of third square = = 6 cm
required perimeter = 6*4 = 24cm
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