when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cm
Area of field = = 96x sq.m
96x = 1440 => x = = 15
Hence, the length of longer parallel side = 5x = 75m
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) sq.cm
Required number of tiles = 1517 x (902/41) x 41 = 814
Let l = 9 ft.
Then l + 2b = 37
=> 2b = 37 ? l = 37 ? 9 = 28
b = 28/2 = 14 ft.
Area = lb = 9 × 14 = 126 sq. ft.
Take a square of side 4cm and a rectangle having l=6cm and b=2cm
then perimeter of square = perimeter of rectangle
area of square = 16 sq.cm
area of rectangle = 12 sq.cm
Hence a >b
P = 4 x s
P=2(l+b)
l=4b
Draw the diagram. The diagonal of the rectangle is the diameter of the circle. The diagonal is the hypotenuse of a 3,4,5 triangle and is therefore, 5.
Circumference = ?.diameter = 5?
The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers.
Given lb =96
Area of pathway = [(l-4)(b-4)-lb] = 16-4(l+b)
Which cannot be determined. so, data is inadequate.
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