Discussion
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- Question
If length of each side of a rhombus PQRS is 8 cm and ?PQR = 120°, then what is the length (in cm) of QS?
Options- A. 4?5
- B. 6
- C. 8
- D. 12
- Correct Answer
- 8
- 1. A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
Options- A. 315
- B. 385
- C. 415
- D. 485 Discuss
- 2. Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is
Options- A. 12
- B. 32
- C. 42
- D. 52 Discuss
- 3. In measuring the sides of a rectangle, one side is taken 5% in excess and the other 4% in deficit. Find the error percent in the area, calculate from the those measurements.
Options- A. .7%
- B. 0.8%
- C. 0.9%
- D. 0.3% Discuss
- 4. The altitude drawn to the base of an isosceles triangle is 8 cm and the perimeter is 32 cm. Find the area of the triangle.
Options- A. 24
- B. 48
- C. 60
- D. 72 Discuss
- 5. The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ?
Options- A. 12.50 cm
- B. 14.21 cm
- C. 15.98 cm
- D. 17.08 cm Discuss
- 6. The diagonal of the floor of a rectangular closet is 7 12 feet. The shorter side of the closet is 4 12 feet. What is the area of the closet in square feet?
Options- A. 9
- B. 18
- C. 27
- D. 36 Discuss
- 7. If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:
Options- A. 1:1
- B. 1:2
- C. 1:3
- D. 1:4 Discuss
- 8. A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
Options- A. 65m
- B. 45m
- C. 55m
- D. 56m Discuss
- 9. The length of a rope in meter by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is ?
Options- A. 15 mts
- B. 30 mts
- C. 24 mts
- D. 36 mts Discuss
- 10. An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ?
Options- A. Rs. 4082.40
- B. Rs. 1024.21
- C. Rs. 2810.6
- D. Rs. 3214 Discuss
Area problems
Search Results
Correct Answer: 315
Explanation:
Let the areas of the two parts be x and (700-x) hectares
therefore,
So, the two parts are 385 and 315.
Hence, Area of the smaller = 315 hectares
Correct Answer: 42
Explanation:
required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm
= 196 - 154 = 42 sq.cm.
Correct Answer: 0.8%
Explanation:
let x and y be the sides of the rectangle then
correct area =
Error% = %
Correct Answer: 48
Explanation:
Let ABC be the isosceles triangle and AD be the altitude
Let AB = AC = x. Then, BC = (32 - 2x).
Since, in an isosceles triangle, the altitude bisects the base,
so BD = DC = (16 - x).
In triangle ADC,
BC = (32- 2x) = (32 - 20) cm = 12 cm.
Hence, required area =
Correct Answer: 17.08 cm
Explanation:
Let the length of the rectangle = L cm
Then the breadth of the rectangle = (L - 10) cm
Perimeter of a rectangle = 2(L + B) cm
=> 44 = 2(L + L - 10)
=> 44 = 4L - 20
=> 4L = 64
=> L = 16 cm
=> B = L - 10 = 6 cm
Diagonal = = = 17.08 cm
Correct Answer: 27
Explanation:
Other side = = = = 6 ft
Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.
Correct Answer: 1:1
Explanation:
A square and a rhombus on the same base are equal in area
Correct Answer: 56m
Explanation:
perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m
Correct Answer: 30 mts
Explanation:
The cow can graze an area of 2826 sq.m i.e it is able to cover area of circle of 2826 sq.m
Therefore,
=2826
=(2826×7/22) = 899.18 = 900
r = 30 m.
Therefore, the radius of the circle implies the length of the rope = 30 mts.
Correct Answer: Rs. 4082.40
Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
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