Let the length of the rectangle = L cm
Then the breadth of the rectangle = (L - 10) cm
Perimeter of a rectangle = 2(L + B) cm
=> 44 = 2(L + L - 10)
=> 44 = 4L - 20
=> 4L = 64
=> L = 16 cm
=> B = L - 10 = 6 cm
Diagonal = = = 17.08 cm
Total are of all stairs = 50 (20x60 + 30x60)
= 50 (1200 + 1800)
= 50 x 3000
= 150000 sq cm.
Given rate of 100 sq cm = Rs. 4
Then for 150000 sq. cm = ?
=> 4 x 150000/100 = Rs. 6000
area of a square = a² sq cm
length of the diagonal = cm
area of equilateral triangle with side
=
required ratio =
let the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is
=> mts.
Let ABC be the isosceles triangle and AD be the altitude
Let AB = AC = x. Then, BC = (32 - 2x).
Since, in an isosceles triangle, the altitude bisects the base,
so BD = DC = (16 - x).
In triangle ADC,
BC = (32- 2x) = (32 - 20) cm = 12 cm.
Hence, required area =
let x and y be the sides of the rectangle then
correct area =
Error% = %
required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm
= 196 - 154 = 42 sq.cm.
Let the areas of the two parts be x and (700-x) hectares
therefore,
So, the two parts are 385 and 315.
Hence, Area of the smaller = 315 hectares
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