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- Question
In an old Palace there are 50 stairs to go on top floor. Each is 20 cm high, 30 cm wide and 60 cm long. If all the stairs are re-plastered at the rate of Rs. 4 per 100 sq.cm. What is the expenditure ?
Options- A. Rs. 4680
- B. Rs. 7600
- C. Rs. 6000
- D. Rs. 5480
- Correct Answer
- Rs. 6000
ExplanationTotal are of all stairs = 50 (20x60 + 30x60)
= 50 (1200 + 1800)
= 50 x 3000
= 150000 sq cm.
Given rate of 100 sq cm = Rs. 4
Then for 150000 sq. cm = ?
=> 4 x 150000/100 = Rs. 6000
- 1. The circumference of a circle, whose area is 24.64 sq.m
Options- A. 14.64
- B. 16.36
- C. 17.60
- D. 18.40 Discuss
- 2. An equilateral triangle is described on the diagonal of a square. What is the ratio of the area of the triangle to that of the square?
Options- A. 1:2
- B. 1:3
- C. 2:3
- D. 3^(1/2) :2 Discuss
- 3. The diagonals of two squares are in the ratio of 2:5. Find the ratio of their areas.
Options- A. 2:25
- B. 3:25
- C. 4:25
- D. 6:25 Discuss
- 4. What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high ?
Options- A. 13 m
- B. 14 m
- C. 15 m
- D. 16 m Discuss
- 5. The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter
Options- A. Rs.16500
- B. Rs.15500
- C. Rs.17500
- D. Rs.18500 Discuss
- 6. The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ?
Options- A. 12.50 cm
- B. 14.21 cm
- C. 15.98 cm
- D. 17.08 cm Discuss
- 7. The altitude drawn to the base of an isosceles triangle is 8 cm and the perimeter is 32 cm. Find the area of the triangle.
Options- A. 24
- B. 48
- C. 60
- D. 72 Discuss
- 8. In measuring the sides of a rectangle, one side is taken 5% in excess and the other 4% in deficit. Find the error percent in the area, calculate from the those measurements.
Options- A. .7%
- B. 0.8%
- C. 0.9%
- D. 0.3% Discuss
- 9. Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is
Options- A. 12
- B. 32
- C. 42
- D. 52 Discuss
- 10. A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
Options- A. 315
- B. 385
- C. 415
- D. 485 Discuss
Area problems
Search Results
Correct Answer: 17.60
Explanation:
Correct Answer: 3^(1/2) :2
Explanation:
area of a square = a² sq cm
length of the diagonal = cm
area of equilateral triangle with side
=
required ratio =
Correct Answer: 4:25
Explanation:
let the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
Correct Answer: 13 m
Explanation:
The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is
=> mts.
Correct Answer: Rs.16500
Explanation:
l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500
Correct Answer: 17.08 cm
Explanation:
Let the length of the rectangle = L cm
Then the breadth of the rectangle = (L - 10) cm
Perimeter of a rectangle = 2(L + B) cm
=> 44 = 2(L + L - 10)
=> 44 = 4L - 20
=> 4L = 64
=> L = 16 cm
=> B = L - 10 = 6 cm
Diagonal = = = 17.08 cm
Correct Answer: 48
Explanation:
Let ABC be the isosceles triangle and AD be the altitude
Let AB = AC = x. Then, BC = (32 - 2x).
Since, in an isosceles triangle, the altitude bisects the base,
so BD = DC = (16 - x).
In triangle ADC,
BC = (32- 2x) = (32 - 20) cm = 12 cm.
Hence, required area =
Correct Answer: 0.8%
Explanation:
let x and y be the sides of the rectangle then
correct area =
Error% = %
Correct Answer: 42
Explanation:
required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm
= 196 - 154 = 42 sq.cm.
Correct Answer: 315
Explanation:
Let the areas of the two parts be x and (700-x) hectares
therefore,
So, the two parts are 385 and 315.
Hence, Area of the smaller = 315 hectares
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