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- Question
What is the area of an obtuse angled triangle given below with two sides are 8 and 12 and the angle included between two sides is 150 deg?
Options- A. 48 sq units
- B. 24 sq units
- C. 12 sq units
- D. 6 sq units
- Correct Answer
- 24 sq units
ExplanationWe know that,
The area of a triangle with two sides given and included angle
A = 1/2 x product of sides x Sin(angle)
Here the two sides are 8 & 12
Angle = 150
Area = 1/2 x 8 x 12 x sin150
Sin(150) = sin(90+60) = cos(60) = 1/2
A = 48 x 1/2 = 24
Area of the given triangle = 24 sq units.
- 1. A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is
Options- A. 200m
- B. 300m
- C. 400m
- D. 100m Discuss
- 2. A semicircular shaped window has diameter of 63cm. Its perimeter equals
Options- A. 162
- B. 132
- C. 142
- D. 172 Discuss
- 3. The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.40 per metre.
Options- A. 2808
- B. 3808
- C. 4808
- D. 5808 Discuss
- 4. In two triangles, the ratio of the areas is 4 : 3 and the ratio of their heights is 3 : 4. Find the ratio of their bases.
Options- A. 13:9
- B. 16:9
- C. 15:9
- D. 14:9 Discuss
- 5. Find the area of a square, one of whose diagonals is 3.8 m long.
Options- A. 4.22 sq.m
- B. 5.22 sq.m
- C. 6.22 sq.m
- D. 7.22 sq.m Discuss
- 6. A sector of 120 degrees, cut out from a circle, has an area of 66/7 sq cm. Find the radius of the circle.
Options- A. 1cm
- B. 2cm
- C. 3cm
- D. 4cm Discuss
- 7. The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter
Options- A. Rs.16500
- B. Rs.15500
- C. Rs.17500
- D. Rs.18500 Discuss
- 8. What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high ?
Options- A. 13 m
- B. 14 m
- C. 15 m
- D. 16 m Discuss
- 9. The diagonals of two squares are in the ratio of 2:5. Find the ratio of their areas.
Options- A. 2:25
- B. 3:25
- C. 4:25
- D. 6:25 Discuss
- 10. An equilateral triangle is described on the diagonal of a square. What is the ratio of the area of the triangle to that of the square?
Options- A. 1:2
- B. 1:3
- C. 2:3
- D. 3^(1/2) :2 Discuss
Area problems
Search Results
Correct Answer: 200m
Explanation:
Let the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
Area of triangle =
Area of rectangle = b*h2
As per Given,
h1=200
Correct Answer: 162
Explanation:
perimeter of window = r+2r
= [(22/7) x (63/2) + 63] = 99+63 = 162 cm
Correct Answer: 5808
Explanation:
Area = (13.86 x 10000) sq.m = 138600 sq.m
Circumference =
Cost of fencing = Rs. (1320 x 4.40) = Rs. 5808.
Correct Answer: 16:9
Explanation:
Let the bases of the two triangles be x and y and their heights be 3h and 4h respectively.
Then,
Required ratio = 16 : 9.
Correct Answer: 7.22 sq.m
Explanation:
Area of the square = = 1/2 * 3.8 * 3.8 = 7.22 sq.m
Correct Answer: 3cm
Explanation:
r =3
Correct Answer: Rs.16500
Explanation:
l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500
Correct Answer: 13 m
Explanation:
The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is
=> mts.
Correct Answer: 4:25
Explanation:
let the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
Correct Answer: 3^(1/2) :2
Explanation:
area of a square = a² sq cm
length of the diagonal = cm
area of equilateral triangle with side
=
required ratio =
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