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- Question
A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is
Options- A. 200m
- B. 300m
- C. 400m
- D. 100m
- Correct Answer
- 200m
ExplanationLet the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
Area of triangle =
Area of rectangle = b*h2
As per Given,
h1=200
- 1. A semicircular shaped window has diameter of 63cm. Its perimeter equals
Options- A. 162
- B. 132
- C. 142
- D. 172 Discuss
- 2. The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.40 per metre.
Options- A. 2808
- B. 3808
- C. 4808
- D. 5808 Discuss
- 3. In two triangles, the ratio of the areas is 4 : 3 and the ratio of their heights is 3 : 4. Find the ratio of their bases.
Options- A. 13:9
- B. 16:9
- C. 15:9
- D. 14:9 Discuss
- 4. Find the area of a square, one of whose diagonals is 3.8 m long.
Options- A. 4.22 sq.m
- B. 5.22 sq.m
- C. 6.22 sq.m
- D. 7.22 sq.m Discuss
- 5. How many square units in 13 by 9?
Options- A. 13
- B. 9
- C. 117
- D. 13/9 Discuss
- 6. What is the area of an obtuse angled triangle given below with two sides are 8 and 12 and the angle included between two sides is 150 deg?
Options- A. 48 sq units
- B. 24 sq units
- C. 12 sq units
- D. 6 sq units Discuss
- 7. A sector of 120 degrees, cut out from a circle, has an area of 66/7 sq cm. Find the radius of the circle.
Options- A. 1cm
- B. 2cm
- C. 3cm
- D. 4cm Discuss
- 8. The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter
Options- A. Rs.16500
- B. Rs.15500
- C. Rs.17500
- D. Rs.18500 Discuss
- 9. What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high ?
Options- A. 13 m
- B. 14 m
- C. 15 m
- D. 16 m Discuss
- 10. The diagonals of two squares are in the ratio of 2:5. Find the ratio of their areas.
Options- A. 2:25
- B. 3:25
- C. 4:25
- D. 6:25 Discuss
Area problems
Search Results
Correct Answer: 162
Explanation:
perimeter of window = r+2r
= [(22/7) x (63/2) + 63] = 99+63 = 162 cm
Correct Answer: 5808
Explanation:
Area = (13.86 x 10000) sq.m = 138600 sq.m
Circumference =
Cost of fencing = Rs. (1320 x 4.40) = Rs. 5808.
Correct Answer: 16:9
Explanation:
Let the bases of the two triangles be x and y and their heights be 3h and 4h respectively.
Then,
Required ratio = 16 : 9.
Correct Answer: 7.22 sq.m
Explanation:
Area of the square = = 1/2 * 3.8 * 3.8 = 7.22 sq.m
Correct Answer: 117
Explanation:
Number of square units in 13 by 9 is given by the area it forms with length and breadth as 13 & 9
Area = 13 x 9 = 117
Hence, number of square units in 13 by 9 is 117 sq.units.
Correct Answer: 24 sq units
Explanation:
We know that,
The area of a triangle with two sides given and included angle
A = 1/2 x product of sides x Sin(angle)
Here the two sides are 8 & 12
Angle = 150
Area = 1/2 x 8 x 12 x sin150
Sin(150) = sin(90+60) = cos(60) = 1/2
A = 48 x 1/2 = 24
Area of the given triangle = 24 sq units.
Correct Answer: 3cm
Explanation:
r =3
Correct Answer: Rs.16500
Explanation:
l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500
Correct Answer: 13 m
Explanation:
The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is
=> mts.
Correct Answer: 4:25
Explanation:
let the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
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