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- Question
The difference between circumference and semidiameter of a circle is 37 cm. What is the diameter of the circle ?
Options- A. 18 cm
- B. 12 cm
- C. 16 cm
- D. 14 cm
- Correct Answer
- 14 cm
Explanationcircumference of a circle = 2 r
=> 2 × 22/7 × r ? r = 37
=> 37/7 × r = 37
=> r = 7 cm.
Diameter D = 2r = 7×2 = 14 cm.
- 1. A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is
Options- A. 64%
- B. 74%
- C. 84%
- D. 94% Discuss
- 2. The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?
Options- A. 47500
- B. 37500
- C. 57500
- D. 77500 Discuss
- 3. A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?
Options- A. 10ft
- B. 20ft
- C. 30ft
- D. 40ft Discuss
- 4. The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is
Options- A. 240
- B. 140
- C. 40
- D. 340 Discuss
- 5. If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
Options- A. 20
- B. 30
- C. 40
- D. 50 Discuss
- 6. A wheel makes 1000 revolutions in covering a distance of 88 km. Find the radius of the wheel.
Options- A. 14
- B. 13
- C. 12
- D. 11 Discuss
- 7. If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area ?
Options- A. 108 sq.cm
- B. 112 sq.cm
- C. 116 sq.cm
- D. 120 sq.cm Discuss
- 8. Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.
Options- A. 25 sq.cm
- B. 16 sq.cm
- C. 9 sq.cm
- D. 4 sq.cm Discuss
- 9. A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
Options- A. 22
- B. 44
- C. 66
- D. 88 Discuss
- 10. The breadth of a rectangular field is 75% of its length. If perimeter of the field is 1050 m, what will be th area of field ?
Options- A. 65700 sq.m
- B. 54500 sq.m
- C. 78700 sq.m
- D. 67500 sq.m Discuss
Area problems
Search Results
Correct Answer: 64%
Explanation:
Area of the sheet =
Area used for typing =
required % = =64%
Correct Answer: 37500
Explanation:
Let length = x meters, then breadth = 0.6x
Given that perimeter = 800 meters
=> 2[ x + 0.6x] = 800
=> x = 250 m
Length = 250m and breadth = 0.6 x 250 = 150m
Area = 250 x 150 = 37500 sq.m
Correct Answer: 20ft
Explanation:
let the radius of the pool be Rft
Radius of the pool including the wall = (R+4)ft
Area of the concrete wall = = sq feet
=> 8
Radius of the pool R = 20ft
Correct Answer: 140
Explanation:
distance covered in 1 revolution =
= 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140
Correct Answer: 50
Explanation:
Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.
Correct Answer: 14
Explanation:
Distance covered in one revolution = = 88m.
Correct Answer: 120 sq.cm
Explanation:
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle =1/2 x base x height => 1/2 x 24 x 10 = 120 sq.cm
Correct Answer: 25 sq.cm
Explanation:
Given length of the rectangle = 3 cm
Breadth of the rectangle = 4 cm
Then, the diagonal of the rectangle
Then, it implies side of square = 5 cm
We know that Area of square = S x S = 5 x 5 = 25 sq.cm.
Correct Answer: 88
Explanation:
We have: l = 20 ft and lb = 680 sq. ft.So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.
Correct Answer: 67500 sq.m
Explanation:
Let the length be 'l' and breadth be 'b'.
b = l × 3/4__________(a)
2(l+b) = 1050
l+b = 525___________(b)
From equations (a) and (b),
l = 300m, b = 225 m
Area = l × b
= 300 × 225
= 67500 sq.m.
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