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- Question
A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet?
Options- A. 378
- B. 472.5
- C. 496
- D. 630
- Correct Answer
- 378
- 1. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 40
- B. 20
- C. 30
- D. none of these Discuss
- 2. The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
Options- A. 27 and 23
- B. 24 and 23
- C. 25 and 23
- D. 22 and 23 Discuss
- 3. The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made.
Options- A. 312 sq.cm
- B. 128 sq.cm
- C. 412 sq.cm
- D. 246 sq.cm Discuss
- 4. The area of the circle is 220 sq.m, the area of the square inscribed in a circle will be
Options- A. 49
- B. 70
- C. 140
- D. 150 Discuss
- 5. Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm?
Options- A. 121 sq.com
- B. 154 sq.com
- C. 186 sq.com
- D. 164 sq.com Discuss
- 6. Find the ratio of the areas of the incircle and circumcircle of a square.
Options- A. 1:1
- B. 1:2
- C. 1:3
- D. 1:4 Discuss
- 7. The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
Options- A. 333 sq.mts
- B. 330 sq.mts
- C. 362 sq.mts
- D. 432 sq.mts Discuss
- 8. What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?
Options- A. 814
- B. 714
- C. 614
- D. 713 Discuss
- 9. A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
Options- A. 65m
- B. 45m
- C. 55m
- D. 56m Discuss
- 10. The length and the breadth of rectangular field are in the ratio of 8 : 7. If charges of the painting the boundary of rectangle is at Rs. 10 per meter is Rs. 3000. What is the area of rectangular plot?
Options- A. 5600 sq.m
- B. 1400 sq. m
- C. 4400 sq.m
- D. 3600 sq.m Discuss
Area problems
Search Results
Correct Answer: none of these
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter =5300/23.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Correct Answer: 27 and 23
Explanation:
Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And,
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm.
Correct Answer: 128 sq.cm
Correct Answer: 140
Explanation:
area of a square =
Correct Answer: 154 sq.com
Explanation:
We know that,
Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides)
= 1/2 x (12 + 10) x 14
= 22 x 14/2
= 22 x 7
= 154 sq. cm
Correct Answer: 1:2
Explanation:
Let the side of the square be x. Then, its diagonal =
Radius of incircle =
Radius of circum circle=
Required ratio =
Correct Answer: 432 sq.mts
Explanation:
Let the breadth of the rectangle = b mts
Then Length of the rectangle = b + 6 mts
Given perimeter = 84 mts
2(L + B) = 84 mts
2(b+6 + b) = 84
2(2b + 6) = 84
4b + 12 = 84
4b = 84 - 12
4b = 72
b = 18 mts
=> Length = b + 6 = 18 + 6 = 24 mts
Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts
Correct Answer: 814
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile =
Required number of tiles = = 814
Correct Answer: 56m
Explanation:
perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m
Correct Answer: 5600 sq.m
Explanation:
Perimeter of the rectangle is given by 3000/10 = 300 mts
But we know,
The Perimeter of the rectangle = 2(l + b)
Now,
2(8x + 7x) = 300
30x = 300
x = 10
Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.
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