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- Question
Square units 13 by 9 of an office area is
Options- A. 97
- B. 117
- C. 107
- D. 127
- Correct Answer
- 117
ExplanationSquare units 13 by 9 of an office means office of length 13 units and breadth 9 units.
Now its area is 13x 9 = 117 square units or units square.
- 1. Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.
Options- A. 56m
- B. 16m
- C. 14m
- D. 76m Discuss
- 2. The area of a circle of radius 5 is numerically what percent its circumference?
Options- A. 150%
- B. 250%
- C. 350%
- D. 450% Discuss
- 3. A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece?
Options- A. 28 cm
- B. 3.5 cm
- C. 7 cm
- D. 14 cm Discuss
- 4. The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?
Options- A. 20 m
- B. 30 m
- C. 40 m
- D. 50 m Discuss
- 5. The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?
Options- A. 10cm
- B. 20cm
- C. 30cm
- D. 40cm Discuss
- 6. Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm?
Options- A. 121 sq.com
- B. 154 sq.com
- C. 186 sq.com
- D. 164 sq.com Discuss
- 7. The area of the circle is 220 sq.m, the area of the square inscribed in a circle will be
Options- A. 49
- B. 70
- C. 140
- D. 150 Discuss
- 8. The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made.
Options- A. 312 sq.cm
- B. 128 sq.cm
- C. 412 sq.cm
- D. 246 sq.cm Discuss
- 9. The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
Options- A. 27 and 23
- B. 24 and 23
- C. 25 and 23
- D. 22 and 23 Discuss
- 10. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 40
- B. 20
- C. 30
- D. none of these Discuss
Area problems
Search Results
Correct Answer: 56m
Explanation:
clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.
Let the length of the rope be r mts
then,
Correct Answer: 250%
Explanation:
required percentage = %
Correct Answer: 14 cm
Explanation:
Circular piece is 4 x 11 = 44 cm long,
Then Circumference of circle is given by,
44 = pi x D, where D is the diameter
D = 44 / pi
Take pi = 22 / 7, then
D = 44 / (22/7) = (44 x 7) / 22
D = 14 cm.
Correct Answer: 20 m
Explanation:
Let breadth=x meters. Then, Length = meters
Given that,
=> x = 20
Breadth = 20
Correct Answer: 20cm
Explanation:
Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is
after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)=
since new area is 75 units greater than original area thus
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.
Correct Answer: 154 sq.com
Explanation:
We know that,
Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides)
= 1/2 x (12 + 10) x 14
= 22 x 14/2
= 22 x 7
= 154 sq. cm
Correct Answer: 140
Explanation:
area of a square =
Correct Answer: 128 sq.cm
Correct Answer: 27 and 23
Explanation:
Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And,
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm.
Correct Answer: none of these
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter =5300/23.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
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