Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is
after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)=
since new area is 75 units greater than original area thus
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.
Let inner radius be r metres. Then, 2 r = 440 ; r = = 70 m.
Radius of outer circle = (70 + 14) m = 84 m.
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) = 2520 sq.m
Area = 5.5 × 3.75 sq. metre.
Cost for 1 sq. metre. = Rs. 800
Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500
perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800
area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m
cost of graveling = 344 x (75/100) = Rs. 258
Let breadth=x meters. Then, Length = meters
Given that,
=> x = 20
Breadth = 20
Circular piece is 4 x 11 = 44 cm long,
Then Circumference of circle is given by,
44 = pi x D, where D is the diameter
D = 44 / pi
Take pi = 22 / 7, then
D = 44 / (22/7) = (44 x 7) / 22
D = 14 cm.
required percentage = %
clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.
Let the length of the rope be r mts
then,
Square units 13 by 9 of an office means office of length 13 units and breadth 9 units.
Now its area is 13x 9 = 117 square units or units square.
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