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- Question
A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be
Options- A. 7744
- B. 8844
- C. 5544
- D. 4444
- Correct Answer
- 7744
Explanationlength of wire = = 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm - 1. A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?
Options- A. 10%
- B. 20%
- C. 30%
- D. 40% Discuss
- 2. The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
Options- A. 22%
- B. 33%
- C. 44%
- D. 55% Discuss
- 3. A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is
Options- A. 136
- B. 236
- C. 336
- D. 436 Discuss
- 4. The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Options- A. 18
- B. 28
- C. 38
- D. 48 Discuss
- 5. If the radius of a circle is decreased by 50% , find the percentage decrease in its area.
Options- A. 75%
- B. 65%
- C. 35%
- D. 25% Discuss
- 6. The ratio of the area of a square to that of the square drawn on its diagonal is
Options- A. 1:2
- B. 2;3
- C. 3:1
- D. 4:1 Discuss
- 7. The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is
Options- A. 49
- B. 154
- C. 378
- D. 1078 Discuss
- 8. The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle?
Options- A. 50
- B. 60
- C. 70
- D. 80 Discuss
- 9. The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.
Options- A. B=900;H=300
- B. B=300;H=900
- C. B=600;H=700
- D. B=500;H=900 Discuss
- 10. A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is
Options- A. Rs. 258
- B. Rs. 358
- C. Rs. 458
- D. Rs. 558 Discuss
Area problems
Search Results
Correct Answer: 30%
Explanation:
let the side of the square be x meters
length of two sides = 2x meters
diagonal =
= 1.414x m
saving on 2x meters = .59x m
saving % = %
= 30% (approx)
Correct Answer: 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = and Increased breadth =
New area =
The difference between the Original area and New area is:
Increase % = = 44%
Correct Answer: 336
Explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC =
= = 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
Correct Answer: 18
Explanation:
(or)
Also,
= 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
Correct Answer: 75%
Explanation:
let original radius = r and new radius = (50/100) r = r/2
original area =
and new area =
decrease in area =
*
*100 = 75%
Correct Answer: 1:2
Explanation:
ratio =
Correct Answer: 154
Explanation:
The diameter is equal to the shortest side of the rectangle.
So radius= 14/2 = 7cm.
Therefore,
Correct Answer: 60
Explanation:
let ABC be the isosceles triangle, the AD be the altitude
Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]
since in an isoceles triange the altitude bisects the base so
BD = DC = 16-x
In a triangle ADC,
BC = 32-2x = 32-20 = 12 cm
Hence, required area = = = 60 sq cm
Correct Answer: B=900;H=300
Explanation:
Area of the field = Total cost/rate = (333.18/25.6) = 13.5 hectares
Let altitude = x metres and base = 3x metres.
Then,
Base = 900 m and Altitude = 300 m.
Correct Answer: Rs. 558
Explanation:
Area to be plastered =
=
Cost of plastering =
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