Discussion
Home ‣ Aptitude ‣ Area Comments
- Question
The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
Options- A. 22%
- B. 33%
- C. 44%
- D. 55%
- Correct Answer
- 44%
ExplanationLet original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = and Increased breadth =
New area =
The difference between the Original area and New area is:
Increase % = = 44%
- 1. A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is
Options- A. 136
- B. 236
- C. 336
- D. 436 Discuss
- 2. The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Options- A. 18
- B. 28
- C. 38
- D. 48 Discuss
- 3. If the radius of a circle is decreased by 50% , find the percentage decrease in its area.
Options- A. 75%
- B. 65%
- C. 35%
- D. 25% Discuss
- 4. If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.
Options- A. 110
- B. 120
- C. 130
- D. 140 Discuss
- 5. If each side of a square is increased by 25%, find the percentage change in its area.
Options- A. 56.25%
- B. 36.25%
- C. 16.25%
- D. 12.25% Discuss
- 6. A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?
Options- A. 10%
- B. 20%
- C. 30%
- D. 40% Discuss
- 7. A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be
Options- A. 7744
- B. 8844
- C. 5544
- D. 4444 Discuss
- 8. The ratio of the area of a square to that of the square drawn on its diagonal is
Options- A. 1:2
- B. 2;3
- C. 3:1
- D. 4:1 Discuss
- 9. The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is
Options- A. 49
- B. 154
- C. 378
- D. 1078 Discuss
- 10. The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle?
Options- A. 50
- B. 60
- C. 70
- D. 80 Discuss
Area problems
Search Results
Correct Answer: 336
Explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC =
= = 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
Correct Answer: 18
Explanation:
(or)
Also,
= 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
Correct Answer: 75%
Explanation:
let original radius = r and new radius = (50/100) r = r/2
original area =
and new area =
decrease in area =
*
*100 = 75%
Correct Answer: 120
Explanation:
let length = x and breadth = y then
2(x+y) = 46 => x+y = 23
x²+y² = 17² = 289
now (x+y)² = 23²
=> x²+y²+2xy= 529
=> 289+ 2xy = 529
=> xy = 120
area = xy = 120 sq.cm
Correct Answer: 56.25%
Explanation:
Let each side of the square be a. Then, area = .
New side =
. New area =
=
Increase in area =
Increase% =
% = 56.25%.
Correct Answer: 30%
Explanation:
let the side of the square be x meters
length of two sides = 2x meters
diagonal =
= 1.414x m
saving on 2x meters = .59x m
saving % = %
= 30% (approx)
Correct Answer: 7744
Explanation:
length of wire =
= 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm
Correct Answer: 1:2
Explanation:
ratio =
Correct Answer: 154
Explanation:
The diameter is equal to the shortest side of the rectangle.
So radius= 14/2 = 7cm.
Therefore,
Correct Answer: 60
Explanation:
let ABC be the isosceles triangle, the AD be the altitude
Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]
since in an isoceles triange the altitude bisects the base so
BD = DC = 16-x
In a triangle ADC,
BC = 32-2x = 32-20 = 12 cm
Hence, required area = = = 60 sq cm
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.