Let the weight of vessel be x
Weight of water = 24 ? x
? (24 ? x)/4 + x = 9
? 24 ? x + 4x = 36
? 3x = 12
? x = 4 kg
Let initial quantity of milk & water in the mixture are 5x & 4x
2 litres water is added.
Hence,
New quantity of milk & water will be 5x & (4x+2)
ATQ,
5x/(4x+2) = 10/9
x/(4x+2) = 2/9 9x = 8x + 4
x=4
Hence,
New amount of water in the mixture = 4x+2 = (4*4) + 2 = 18 litres.
Amount of pure milk= a(1 ?b/a)n(n = 3, a = pure milk and b = amount replaced)= 960 (1 ?48/960)^3= 960(1-1/20)^3= 960 * 19/20 * 19/20*19/20= 823.08 lt.
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