As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.
From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)
As per question for deadly,
U is more deadly than Z
1. U > Z.
V is less deadly than Z.
2. V < Z.
W is less deadly than U.
3. W < U.
X is more deadly than Y.
4. X > Y.
Y is more deadly than U.
5. Y > U.
Z is less deadly than W.
6. Z < W.
Now from 1 and 2,
7. U > Z > V
from 7 and 5,
8. Y > U > Z > V
from 4 and 8,
9. X > Y > U > Z > V
from 3, 6 and 9,
X > Y > U > W > Z > V
Effectiveness (deadly) X, Y, U, W, Z, V
Statement V does not add any new information about the sweetness of compound.
The compound can be arranged according to their taste and effectiveness as shown below.
Taste (sweet) Z, U, V, Y, X, WW
Effectiveness (deadly) X, Y, U, W, Z, V
Compound U is sweeter than Y and More deadly and W.
As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.
From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)
As per question for deadly,
U is more deadly than Z
1. U > Z.
V is less deadly than Z.
2. V < Z.
W is less deadly than U.
3. W < U.
X is more deadly than Y.
4. X > Y.
Y is more deadly than U.
5. Y > U.
Z is less deadly than W.
6. Z < W.
Now from 1 and 2,
7. U > Z > V
from 7 and 5,
8. Y > U > Z > V
from 4 and 8,
9. X > Y > U > Z > V
from 3, 6 and 9,
X > Y > U > W > Z > V
Effectiveness (deadly) X, Y, U, W, Z, V
It is clear that both Z and U are sweeter and more deadly than V.
As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.
From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)
From the above taste (sweet) ranking, we find that Z is the sweetest.
Given, Siya > Priya > Tiya ........(i)
Siya > Riya > Priya ........(ii)
and Riya > Tiya > Diya .........(iii)
On combining Eqs. (i), (ii) and (iii), we get
Siya > Riya > Priya > Tiya > Diya
According to the question,
A + B = C + D; B + D > A + C; A > B
Now, B + D > A + C and A > B
? B + D > A + C > B + C ? B + D > B + C ? D > C
Now, B + D > A + C ? B + D = A + C + K
Also, A + B = C + D ? B - D = C - A
? 2B = 2C + K ? B > C ? A > B > C
D > C
Clearly, each one of A, D and b has more amount than C. Hence, C has the least amount.
As per question for deadly,
U is more deadly than Z
1. U > Z.
V is less deadly than Z.
2. V < Z.
W is less deadly than U.
3. W < U.
X is more deadly than Y.
4. X > Y.
Y is more deadly than U.
5. Y > U.
Z is less deadly than W.
6. Z < W.
Now from 1 and 2,
7. U > Z > V
from 7 and 5,
8. Y > U > Z > V
from 4 and 8,
9. X > Y > U > Z > V
from 3, 6 and 9,
X > Y > U > W > Z > V
Effectiveness (deadly) X, Y, U, W, Z, V
Compound V is the least deadly.
As per question for deadly,
U is more deadly than Z
1. U > Z.
V is less deadly than Z.
2. V < Z.
W is less deadly than U.
3. W < U.
X is more deadly than Y.
4. X > Y.
Y is more deadly than U.
5. Y > U.
Z is less deadly than W.
6. Z < W.
Now from 1 and 2,
7. U > Z > V
from 7 and 5,
8. Y > U > Z > V
from 4 and 8,
9. X > Y > U > Z > V
from 3, 6 and 9,
X > Y > U > W > Z > V
Effectiveness (deadly) X, Y, U, W, Z, V
Compound X is the most deadly.
According to the question,
P was more effective than Q.
1. P > Q.
The effectiveness of R was less than that of S.
2. S > R.
T was the least effective brand tested.
3. T is least effective.
Q and R were equally effective.
4. Q = R.
The effectiveness of S was greater than that of Q.
5. S > Q.
from 1 and 5 ,
6. S/P > Q .
from 6 and 4 ,
7. S/P > Q = R .
from 7 and 3 ,
? S/P > Q = R > T
R was less effective than p.
According to the question,
P > Q. S > R
T is least effective Q = R, S > Q
? S/P > Q = R > T
Statement V is not required.
According to the question,
P > Q. S > R
T is least effective Q = R, S > Q
? S/P > Q = R > T
It is clear from the ranking order so obtained that brand S may be less effective than P, equal to P or more effective than P. It means that position of S is not fixed. Now as per question, sixth band i.e, M is more effective than S which implies that whatever be the position of S, there will be atleast four brands which will be less effective than M.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.