In a class among the passed students neeta is 22nd from the top and Kalyan, who is 5 ranks below Neeta is 34th from the bottom. All the students from the class appeared for an examination. If the ratio of the students who passed in the examination to those who failed is 4 : 1 for the class, how many students were there in the class?

Position of Rekha is 20th from the right which is occupied by Jaya after interchanging takes place and Jaya becomes 22nd from the left. Therefore, total number of students in the row.
(20 + 22) - 1 = 41

Dilip is 10th from the left and the same position is occupied by Jagdish after interchanging takes place and he becomes 23rd from the right.
Therefore, total number of student in the row = (10 + 23) - 1 = 32

The total number of students cannot be determined because the ranks of Sairam from top and bottom is given for different subjects. So, the given information is not sufficient. Hence, option (d) is correct.

Given number = 53146872
After interchanging the digits,
New number = 68725314
Hence, fifth digit from the right end = 2

Total number of students = Total of both side rank - 1 = 21 + 30 - 1 = 50

_______________________________________________
According to        | Leave Date
__________________|____________________________
Seema                   | 22, 23, 24, 25, 26
__________________|_____________________________
but Seema was present on 23rd. Also, it was holiday on 24th and 26th October was Sunday. Hence, possible date may be either 22nd or 25th October

According to question,
R is heavier than S but lighter than T.
R > S But T > R
Then T > R > S
P is lighter than S.
S > P
Then
T > R > S, S > P ? T > R > S > P
But information about Q is not given, Hence, either T or Q is the heaviest.

According to the question,
A + B = C + D; B + D > A + C; A > B
Now, B + D > A + C and A > B
? B + D > A + C > B + C ? B + D > B + C ? D > C
Now, B + D > A + C ? B + D = A + C + K
Also, A + B = C + D ? B - D = C - A
? 2B = 2C + K ? B > C ? A > B > C
D > C
Clearly, each one of A, D and b has more amount than C. Hence, C has the least amount.

Given, Siya > Priya > Tiya ........(i)
Siya > Riya > Priya ........(ii)
and Riya > Tiya > Diya .........(iii)
On combining Eqs. (i), (ii) and (iii), we get
Siya > Riya > Priya > Tiya > Diya

As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.

From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)

From the above taste (sweet) ranking, we find that Z is the sweetest.