According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Bina occupies the third position from the top
According to the question,
Rama > Rani, Rani < Ratna, Ratna > Rama
and Ratna > Padma > Rama
On arranging the above data, we get
? Ratna > Padma > Rama > Rani
So, Ratna scored the highest.
If A won ? 4000, then the only possible ranking is
C- 12000, F - 10000
E - 8000, B- 6000
A - 4000, D - 2000
The total of C and F = 12000 + 1000 = 22000
Try All option one by one.
Out of all the given options, only the ranking given in (d) satisfies the given conditions.
B - 12000 A won less money than B)
A - 10000
E - 8000
D - 6000
C - 4000 and the difference between winning of C and F was ? 2000.
F - 2000 and the difference between winning of D and F was at least ? 4000.
According to question,
Gita is older than her cousin Mita.
1. G > M
Mita's brother Bhanu is older than Gita.
2. B > G
From 1 and 2,
B > G > M
Gita >Mita ; Bhanu > Gita
? Bhanu > Gita > Mita
When Mita and Bhanu are visiting Gita, all three like to play a game of Monopoly. Mita wins more often than Gita does.
According to given information as per height,
Eswer is taller than Debu.
E > D
Charu is taller than Anil but shorter than Bibek
C > A But C < B
Arrangement of heights in descending order
Bibek > Charu > Anil > Eswer > Debu
Arrangement of weights in descending order
Eswer is taller than Debu but not as fat as Debu.
1. D > E (Debu is fatter than Eswer)
Anil is fatter than Debu but not as fat as Bibek.
2. A > D But B > A
Eswer is thinner than Anil.
3. E < A
From 1 and 3
4. A or D > E
from 2 and 4 ,
5. B > A > D > E
Bibek > Anil > Debu > Charu > Eswer
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Third
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Seema is shortest.
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Gauri is tallest among them.
According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
Descending order of weights of the articles will be
A, B, E, D, C
According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
So A is the heaviest in the weight.
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