As per the given information C has more amount than only E/B/A. So, it means D > C > E / B / A arrangement can be established.
So, D has maximum amount of money.
After interchanging first first and second digit, number are
849, 451, 564, 593, 873.
Hence, third highest number = 593 ? 953
489 ? 484, 541 ? 536, 654 ? 649,
953 ? 948, 783 ? 778
Hence, required difference = 7 - 4
= 3
Arranging all the digits in ascending order, we get
489, 145, 456, 359, 378
Hence , lowest number = 145 ? 541
After interchanging the first and the last digit, numbers are 984, 145, 456, 359, 387
Hence, second highest number = 456 means 654.
Ascending order 1 2 3 4 5 7 8 9
? Required difference = 5 - 3 = 2
On the basis of give information,
Order of ranking of height in the question of variable nature as it cannot be established whether Harish is taller than Suresh or not. The given information not complete to bring a relationship between Harish and Suresh.
So it cannot be determined who is the shortest.
According to question,
Roshan is taller than Hardik who is shorter than Sushil.
R > Hardik But Hardik < S.
Niza is taller than Harry but shorter than Hardik.
N > Harry But N < Hardik
Sushil is shorter than Roshan.
S < R
Descending order of the heights is as
Roshan > Sushil > Hardik > Niza > Harry.
Therefore, the tallest person is Roshan.
According to given question,
Vasant is taller than Manohar but not as tall as Raju.
V > M But R > V.
Jayant is taller than Dutta But shorter than Manohar.
J > D But M > J.
So V > M and M > J
Then V > M > J
R > V and J > D
Then R > V > M > J >D
Descending order of the heights is as
Raju > Vasant > Manohar > Jayant > Dutta
Hence, Raju is the tallest.
From the given condition,
Sudha scored higher than Puja.
Sudha > Puja
Kavita scored lower than Suma but higher than Sudha.
Kavita < Suma But Kavita > Sudha
Therefore Suma > Kavita > Sudha > Puja
Mamta scored between Puja and Sudha.
Then Suma > Kavita > Sudha > Mamta > Puja data is arranged as
Suma > Kavita > Sudha > Mamta > Puja
Hence, Puja scored lowest in the examination.
According to given information as per height,
Eswer is taller than Debu.
E > D
Charu is taller than Anil but shorter than Bibek
C > A But C < B
Arrangement of heights in descending order
Bibek > Charu > Anil > Eswer > Debu
Arrangement of weights in descending order
Eswer is taller than Debu but not as fat as Debu.
1. D > E (Debu is fatter than Eswer)
Anil is fatter than Debu but not as fat as Bibek.
2. A > D But B > A
Eswer is thinner than Anil.
3. E < A
From 1 and 3
4. A or D > E
from 2 and 4 ,
5. B > A > D > E
Bibek > Anil > Debu > Charu > Eswer
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