As per the given figure , we can see that
Let the toll charged at junctions A, B, C and D be a, b, c and d respectively.
Then 1st we will list down all the routes and corresponding cost of travel.
Since Route BC is under repair hence route S-B-C-T is not in use.
Rest all four have the same toll charges hence 14 + a = 9 + a + b ? b = 14 - 9 = 5
Similarly 10 + c + d = 13 + d ? c = 13 - 10 = 3
Hence Options 4 is ruled out, now if we check option rest 3 options we will find out that option 2 and 3 both are correct. Option (2)/(3) Inconsistent options .
From option (c),
8 * 8 * 1 * 7 = 8
? 8 ÷ 8 x 1 + 7 = 8
? 8 = 8
Statements
P < Q = R ? S ? T
Conclusions
I. T ? Q (true)
II. R > P (true)
Hence, both conclusions are definitely true.
If we interchanges signs '+' and '÷', then the equation changes into
15 + 9 x 3 - 74 ÷ 2 = 15 + 27 - 37 = 5
Solve all option one by one,
36 + 6 - 3 x 2 = 20
After changing the symbol as per question,
36 ÷ 6 x 3 + 2 = 20
Apply the BODMAS rule,
? 6 x 3 + 2 = 20
? 18 + 2 = 20
? 20 = 20
H ? W ..(i) W < N ...(ii) R = N ...(iii)
Combining these we get H ? W < N = R
Hence R > W and I follows
Again N > W and II follows
And, H < R III follows
4 x 3 x 4 = 48
D ? N ...(i) R = F ...(ii) F > T ...(ii)
From (i) and (ii) D ? R = F or D ? F or F ? D.
Hence either I (F = D ) or II (F > D) follows
From (ii) and (iii) R = F > T or R > T or T < R.
Hence III follows.
M < T ... (i) T > K ...(ii) K = D ...(iii)
From (ii) and (iii) T > K = D or D < T.
Hence I follow
From (i) and (ii) K and M can't be compared
Hence II does not follow
N < O ? R > T; R < A; B ? T
Check for I:
N < O ? R > T
? No definite relation can be found between N and A.
Check for II:
Apply all option one by one.
? 6 x 4 + 2 = 16 ? 4 + 6 x 2 = 16 ? 4 + 12 = 16
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