The free capacity available at the Avanti-Vaishali pipeline is

On the basis of above given route network diagram , we can see that
Free capacity in Avanti-Vidisha is zero.
Explanation is similar as in previous answer.

As per the given above figure , we can see that
Since flow from Vaishali to Jyotishmati is 300 where as demand is 400 so the deficient 100 would be met by flow from Vidisha.
Again the demand of 700 in Panchal is again to be met by flow from Jyotishmati which can get it from Vidisha.
Thus, the quantity moved from Avanti to Vidisha is 200 + 100 + 700 = 1000

A child can be without Toys, Education and Friends but cannot be without parents. So child must have had a parents.

.

A mountain has always a height. A mountain cane be without Ranger , Snow and Valley. So a mountain should have the Peak.

As per the given above figure , we can see that
There are four ways to go from A to the first level of nodes. Each of these 4 nodes in turn leads into two more ways to go to the second level nodes.
Each of the second level nodes leads into two more ways to go to the third level nodes.
And from here we have only one way each to go to B.
Hence by fundamental principal of counting, total number of ways = 4 x 2 x 2 x 1 = 16 ways.

According to question ,
It can be seen that every city is connected to all the other cities (i.e. 3 other cities).
Step 1: Let starting point is A, there are 3 ways in which we could proceed, viz. AB, AD or AC.
Step 2: Once we are at any of these cities (B, D or C), each one of them is connected to 3 other cities. But since we cannot go back to A the originating city, there are only 2 ways in which we could proceed from here.
Step 3: let us assume that we are at B, we can only go to D or C by taking BD or BC respectively. From this point we a choice of either directly going back to A (thus skipping 4th city or go to 4th city and come back to A. )
Step 4:- Now if we are at D, we can either take DA or DCA. So there are 2 more ways to go from here.
So , total number of ways = 3 x 2 x 2 = 12 ways.

From the above given figure ,
The maximum quantity of natural gas that S can receive = 6 + 2 + 9 = 17 units.
Therefore , required answer will be 17 units.

We know that cities M and P are gas plants.Hence , option A will be correct answer .

From the above given figure and the conditions R can receive only 6 units (5 + 1) of natural gas if utilization is 100%.
Therefore , required answer will be 6 units.