The movements of the man from A to F are as shown in Figure Clearly,
DC = AB + EF
Therefore, F is in line with A
Also, AF = (BC ? DE) = 5 m.
So, the man is 5 meters away from his initial position.
The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T)
Since TS = OP + QR, so T lies in line with O. A's distance from the starting point O = OT = (RS ? PQ) = (15 ? 10)m = 5 m.
Drawing a figure for the movement of a man as below.
Draw a figure for 1 km towards East.
Then Draw another figure for 5 km in south.
Again draw a line when he turns to East and walks 2 km,
after this draw a line when he turns to North and walks 9 km.
The movements of Sanjeev from A to F are as shown in Figure Clearly,
Sanjeev's distance from starting point A
= AF = (AB + BF) = AB + ( BE ? EF ) = AB + (CD ? EF)
= [10 + (20 ? 10)] m = (10 + 10) m = 20 m.
Also, F lies to the South of A. So, Sanjeev is 20 meters to the south of his starting point.
The movements of Maya from T to R are as shown in Figure.
Distance between T and R = TR = TU + UR = TU + PW + QV = ( 4 + 3 + 1) ft = 8 ft.
Draw a figure.
Rohan walks a distance of 3 km towards North.
Then turns to his left and walks for 2 km.
He again turns left and walks for 3 km.
At this point he turns to his left and walks for 3 km.
It is clear from the diagram that Kamu is to the west of her house.
Hence required answer will be west direction.
From given diagram , It is clear that Janaki is going towards south.So Answer will be south direction .
It is clear from the diagram that Mohan is facing towards North.
Now Suresh is in the East direction from the starting point.
I started my journey from south.
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