Maya starts at point T, Walks straight to point U which is 4 ft away. She turns left at 90° and walks to W which is 4 ft away, turns 90° right and goes 3 ft to P, turns 90° right and walks 1 ft to Q, turns left at 90° and goes to V, which is 1 ft away and once again turns 90° right and goes to R, 3 ft away. What is the distance between T and R?

Draw a figure.
Rohan walks a distance of 3 km towards North.
Then turns to his left and walks for 2 km.
He again turns left and walks for 3 km.
At this point he turns to his left and walks for 3 km.

First move to north direction, then turn right, again turn right without moving from the position than turn left and move.

Draw a figure first when man is moving in clockwise direction then for anticlockwise. The man will be finally standing in North East position as explain in below figure.

Let us assume her house is situated at point A.
Draw a figure of movement of Radhika.

Draw the figure of movement with the help of given below direction graph.
A person starts from a point A and travels 3 km East - Wards to B. Then he turns left and travels 9 km to reach C.
He again turns left and travels 15 km and reaches his destination D.
The movements of the person are as shown in Figure
Clearly, AB = 3 km, BC = 3AB = (3 × 3) km = 9 km, CD = 5AB = (5 × 3) km = 15 km,
Draw AE ? CD.
Then, CE = AB = 3 km
AE = BC = 9 km
DE = (CD ? CE) = (15 ? 3) km = 12 km.
In triangle AED, AD² = AE² + DE²
or AD² = 9² + 12²
or AD² = 81+ 144
or AD² = 225
or AD² = 15²
AD = 15
Required distance = AD = 15 km

The movements of Sanjeev from A to F are as shown in Figure Clearly,
Sanjeev's distance from starting point A
= AF = (AB + BF) = AB + ( BE ? EF ) = AB + (CD ? EF)
= [10 + (20 ? 10)] m = (10 + 10) m = 20 m.
Also, F lies to the South of A. So, Sanjeev is 20 meters to the south of his starting point.

Drawing a figure for the movement of a man as below.
Draw a figure for 1 km towards East.
Then Draw another figure for 5 km in south.
Again draw a line when he turns to East and walks 2 km,
after this draw a line when he turns to North and walks 9 km.

The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T)
Since TS = OP + QR, so T lies in line with O. A's distance from the starting point O = OT = (RS ? PQ) = (15 ? 10)m = 5 m.

The movements of the man from A to F are as shown in Figure Clearly,
DC = AB + EF
Therefore, F is in line with A
Also, AF = (BC ? DE) = 5 m.
So, the man is 5 meters away from his initial position.

It is clear from the diagram that Kamu is to the west of her house.
Hence required answer will be west direction.