The sequence is made of repetition of two blocks acbd and cadb alternatively.
acbd/cadb/acbd/cadb/acbd ? addddb
The sequence is made of repetition of abc in different order, so identify the missing alphabet in abc .
second word is reverse of first word, similar way 4th word is reverse of 3r word.
By option (d),
abc/cba/bca/acb ? bcba
Using the proper symbols in ( c ), we get
5 x 2 ÷ 2 < 10 -4 + 8
After Replacing the Sign Apply the BODMAS Rule.
?  5 x 1 < 18 - 4
?  5 < 14
which is true .
Try all option one by one;
From option (d),
6 * 4 * 12 * 12
Change the sign, as per the question,
6 x 4 - 12 = 12
Apply the BODMAS rule
After Multiplication
24 - 12 = 12
After Substraction
?  12 = 12
Try all option one by one;
From option ( b )
49 - 7 + 3 ÷ 5 x 8 = 24
Change the sign, as per the question,
49 ÷ 7 x 3 - 5 + 8 = 24
Apply the BODMAS rule
B - Brackets first
O - Orders (i.e. Powers and Square Roots, etc.)
DM - Division and Multiplication (left-to-right)
AS - Addition and Subtraction (left-to-right)
Now Applying the BODMAS rule one by one.
49 ÷ 7 x 3 - 5 + 8 = 24
After Division
7 x 3 - 5 + 8 = 24
After Multiplication
21 - 5 + 8 = 24
After Addition
29 - 5 = 24
After subtraction
24 = 24
16 x 2 ÷ 25 + 7 - 4
After replacing the sign according to the given question
16 ÷ 2 + 25 - 7 x 4
Apply the rule BODMAS
B - Brackets first
O - Orders (i.e. Powers and Square Roots, etc.)
DM - Division and Multiplication (left-to-right)
AS - Addition and Subtraction (left-to-right)
= 16 ÷ 2 + 25 - 7 x 4
= 8 + 25 - 28
= 25 - 20
= 5
The sequence is made of repetition of two blocks cab and bac alternatively.
cab/bac/cab/bac/cab/bac ? acbcb
The word aabcd is formed.
2nd word is made by changing to the 2nd position with next alphabet, similarly
3rd word is made by changing to the 3rd position with next alphabet,
4th word is made by changing to the 4th position with next alphabet.
aabcd/abbcd/abccd/abcdd ? adbbad
The series is formed of two repeated alphabet at start and end but middle alphabet is not repeated. The word is formed with the help of combination of reordering of abc.
aabcc/ccabb/bbcaa ? accba
The series is made of two consecutive 'A' and three consecutive 'B' in alternate manner.
AA'B/BB'A/A'AB/B'BA ? ABAB
The given series is combination of yzy and xzx .
Arrange the word as per given suggestion, we will get
yzy/xzx/yzy/xzx/yzy/xzx/y ? yxzyz
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.