12 | 26 | 11 | 36 | 9 | |
7 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
The given series is in the below pattern ,
First series :-
First term = 12
Second term = First term × 2 + 2
? Second term = 12 × 2 + 2 = 26
Third term = Second term ÷ 2 - 2
? Third term = 26 ÷ 2 - 2 = 11
similarly , we can find the all others terms .
........... and so on.
Second series :-
First term = 7
Second term = First term × 2 + 2
? Second term = 7 × 2 + 2 = 16
Third term = Second term ÷ 2 - 2
? Third term = 16 ÷ 2 - 2 = 6
Fourth term = Third term × 3 + 3
? Fourth term = 6 × 3 + 3 = 21
Hence , the place value of ( c ) is 21.
10 | 11 | 15 | 24 | 40 | |
6 | (a) | (b) | (c) | (d) | (e) |
What will come in place of (c)? |
As per the details in the question the series is in the form of
First series :-
First term = 10
Second term = First term + 12
? Second term = 10 + 12 = 10 + 1 = 11
Third term = Second term + 22
? Third term = 11 + 22 = 11 + 4 = 15
similarly , we can find the all others terms .
Second series :-
First term = 6
Second term = First term + 12
? Second term = 6 + 12 = 6 + 1 = 7
Third term = Second term + 22
? Third term = 7 + 22 = 7 + 4 = 11
Fourth term = Third term + 32
? Fourth term = 11 + 32 = 11 + 9 = 20
Hence , the place value of ( c ) is 20 .
2 | 3 | 10 | 39 | 172 | 885 |
5 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (d)? |
As per the details in the question the series is in the form of
First series :-
First term = 2
Second term = First term × 1 + 12
? Second term = 2 × 1 + 1 = 2 + 1 = 3
Third term = Second term × 2 + 22
? Third term = 3 × 2 + 4 = 6 + 4 = 10
similarly , we can find the all others terms .
Second series :-
First term = 5
Second term = First term × 1 + 12
? Second term = 5 × 1 + 1 = 5 + 1 = 6
Third term = Second term × 2 + 22
? Third term = 6 × 2 + 4 = 12 + 4 = 16
Fourth term = Third term × 3 + 32
? Fourth term = 16 × 3 + 9 = 57
Fifth term = Fourth term × 4 + 42
? Fifth term = 49 × 4 + 16 = 244
Hence , the place value of ( d ) is 244 .
3 | 10 | 32 | 111 | 460 | 2315 |
2 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (b)? |
The given series is in the below pattern ,
First series :-
First term = 3
Second term = First term × 1 + 7 × 1
? Second term = 3 × 1 + 7 × 1 = 3 + 7 = 10
Third term = Second term × 2 + 6 × 2
? Third term = 10 × 2 + 6 × 2 = 20 + 12 = 32
similarly , we can calculate the all next terms .
Second series :-
First term = 2
Second term = First term × 1 + 7 × 1
? Second term = 2 × 1 + 7 × 1 = 2 + 7 = 9
Third term = Second term × 2 + 6 × 2
? Third term = 9 × 2 + 6 × 2 = 18 + 12 = 30
Hence , the place value of ( b ) is 30 .
As per the details in the question the series is in the form of
From given figure , it is clear that
Hence the place value of ? is ZKW .
The number of letters in the terms goes on increasing by one at each step. Also, there is a gap of one letter between the last letter of the first term and first letter of the second term and a gap of two letters between the last letter of the second term and first letter of the third term. So, the first letter of the required term would be four steps ahead of the last letter of the third term.
The order of above series given as -
A, CD, GHI , ( ? ) , UVWXY
1 , 3 4 , 7 8 9 , ( 13 14 15 16 ) , 21 22 23 24 25
So ? = MNOP ? 13 14 15 16
Hence , required answer will be MNOP .
4 | 5 | 22 | 201 | ||
12 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (d)? |
The given series is in the below pattern ,
First series :-
First term = 4
Second term = First term × 12 + 1
? Second term = 4 × 12 + 1 = 4 + 1 = 5
Third term = Second term × 22 + 2
? Third term = 5 × 22 + 2 = 20 + 2 = 22
similarly , we can calculate the all next terms .
Second series :-
First term = 12
Second term = First term × 12 + 1
? Second term = 12 × 12 + 1 = 12 + 1 = 13
Third term = Second term × 22 + 2
? Third term = 13 × 22 + 2 = 52 + 2 = 54
Fourth term = Third term × 32 + 3
? Fourth term = 54 × 32 + 3 = 486 + 3 = 489
Fifth term = Fourth term × 42 + 4
? Fifth term = 489 × 42 + 4 = 7824 + 4 = 7828
Hence , the place value of ( d ) is 7828 .
25 | 146 | 65 | 114 | ||
39 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (e)? |
The given series is in the below pattern ,
First series :-
First term = 25
Second term = First term + 112
? Second term = 25 + 112 = 25 + 121 = 146
Third term = Second term - 92
? Third term = 146 - 92 = 146 - 81 = 65
similarly , we can calculate the all next terms .
Second series :-
First term = 39
Second term = First term + 112
? Second term = 39 + 112 = 39 + 121 = 160
Third term = Second term - 92
? Third term = 160 - 92 = 160 - 81 = 79
Fourth term = Third term + 72
? Fourth term = 79 + 72 = 79 + 49 = 128
Fifth term = Fourth term - 52
? Fifth term = 128 - 52 = 128 - 25 = 103
Fifth term = Fourth term - 52
? Sixth term = 103 + 32 = 103 + 9 = 112
So 112 should come in place of (e).
As per the details in the question the series is in the form of
First term = 1
Second term = ( First term × Variable ) + Variable = 2
Third term = ( Second term × Previous Variable + 0.5 ) + Previous Variable + 0.5 = 4.5
Similarly we can find the all others terms
Second term = ( 1 × 1 ) + 1 = 2
Third term = ( 2 × 1.5 ) + 1.5 = 4.5
Fourth term = ( 4.5 × 2 ) + 2 = 11
Fifth term = (11 × 2.5 ) + 2.5 = 30
Sixth term = ( 30 × 3 ) + 3 = 92.5 , 93 should be sixth term because ( 30 × 3 ) + 3 = 93
So 92.5 is wrong. we get 93 as 6th term.
Seventh term = ( 93 × 3.5 ) + 3.5 = 325.5 + 3.5 = 329.
The Order of above given series is
First term + Second term = Third term
? 2 + 5 = 7;
Second term + Third term = Fourth term
? 5 + 7 = 12;
Third term + Fourth term = Fifth term
? 7 + 12 = 19;...
Fourth term + Fifth term = Sixth term
? 12 + 19 = 32 , 31 should be 6th term because 12 + 19 = 31
So 32 is wrong. we get 31 as 6th term.
Fifth term + Sixth term = Seventh term
? 19 + 31 = 50
The given series is in the below pattern,
? First term = 2
Second term = First term × 7
? Second term = 2 × 7 = 14
Similarly we can find the all others terms also.
Third term = Second term × 6.5
? Third term = 14 × 6.5 = 91
Fourth term = Third term × 6
? Fourth term = 91 × 6 = 546
Fifth term = Fourth term × 5.5
? Fifth term = 546 × 5.5 = 3002 is wrong , So 3003 should be Fifth term because ( 546 × 5.5 ) = 3003 .
Sixth term = Fifth term × 5
? Fifth term = 3003 × 5 = 15015.
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