All others have two vowels.
Expect B, all are the vowels.
All others are vowels.
All others are consonants.
In all other pairs, second is a collective group of the first.
In all pairs expert (b) , deficiency of first causes the disease in second part.
The pattern used for classification is placement of alphabets in the order (- 3, - 3, - 3). Since, option (b) dose not follow the pattern, it is odd in the group.
In all other groups, there is a gap of two letters as in the alphabet between third and fourth letters.
In all other groups, there is a gap of two letters as in the alphabet between second and third letters.
Except option (d), sum of all other letters given is equal to 27. And given number represents the possition of lst letters .
Except 'PRU', all others having same gap but 'PRU' is not following the same rule.
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